On Tue, Apr 15, 2025 at 01:43:10PM +0200, Fons Adriaensen wrote: > > Now, to be 'constructive', the correct way to compute c > would be > > f = cutoff_frequency / sample_rate; > a = 2 * (1 - cos (2 * pi * f); > c = (sqrt (a * (a + 4)) - a) / 2; > > > A good approximation (less than 1% relative error) > for 0 <= f <= 0.5 could be > > c = 2 * pi * f * (1 + f * (3.45f + 4.27f * f));
Can you explain how you get there, in terms that a 35-years-ago Straight-Cs highschool maths student might understand? I know how algebra works and kind of how to make calculus work, and enough DSP to be dangerous, but that's about it. -- Gordonjcp _______________________________________________ Linux-audio-dev mailing list -- linux-audio-dev@lists.linuxaudio.org To unsubscribe send an email to linux-audio-dev-le...@lists.linuxaudio.org
