On 21/1/19 3:15 am, Thomas Osterried wrote:
=> Even if you try to use lowercase characters (what will break supposely every
existing packet-radio-software), due to the left shift, you won't be able to
encode letters p-z.

That I find interesting… it's a 7-bit ASCII character in an 8-bit field.

'p' is 0x70 (0b01110000) according to `man ascii`, which left shifted with be 0xe0 (0b11100000).

'z' is 0x7a (0b01111010), which left shifted would be 0xf4 (0b11110100).

Why wouldn't it be possible to encode those letters?
Stuart Longland (aka Redhatter, VK4MSL)

I haven't lost my mind...
  ...it's backed up on a tape somewhere.

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