>Hello,
>
>Could anybody solve this problem? I need to cut the 'SizeOfFile' field from
>the output of ls -l. I don't know what the delimter is but I tried
>ls -l | cut -f5 -d' '
>for which I didn't get the expected result.
Try this
ls -l |tr -s ' '|cut -d ' ' -f5
HTH
--
Anand Biligiri S
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It don't mean a THING if you ain't got that SWING!!
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