> So how are we going to deal with that in the schematas? Assume the L3=16 > and L2=8 case(no CDP). So effectively any write of L2 to CLOSID=0 will > affect the setting of L2 in CLOSID=8. > > Will the code tell the user that L2 cannot be set for CLOSID >= 8? > > Will it print the setting of CLOSID - 8 for CLOSID >= 8 when you read the > schemata file of CLOSID >= 8?
The default and first 7 directories you make will have lines in schemata for both L3 and L2. The next 8 will just have L3 (and won't let you add L2). > And of course this becomes very interesting when CLOSID 1 is deleted, then > what happens to CLOSID 9? Not to talk about the case when CLOSID 1 is > reused again. Deleting CLOSID 1 won't affect CLOSID 9. When you make a new directory that gets allocated CLOSID 1, it will have both L3 and L2 lines. -Tony
