On Mon, 17 Oct 2016, Luck, Tony wrote:
> > So how are we going to deal with that in the schematas? Assume the L3=16
> > and L2=8 case(no CDP). So effectively any write of L2 to CLOSID=0 will
> > affect the setting of L2 in CLOSID=8.
> > Will the code tell the user that L2 cannot be set for CLOSID >= 8?
> > Will it print the setting of CLOSID - 8 for CLOSID >= 8 when you read the
> > schemata file of CLOSID >= 8?
> The default and first 7 directories you make will have lines in schemata for
> both L3 and L2. The next 8 will just have L3 (and won't let you add L2).
> > And of course this becomes very interesting when CLOSID 1 is deleted, then
> > what happens to CLOSID 9? Not to talk about the case when CLOSID 1 is
> > reused again.
> Deleting CLOSID 1 won't affect CLOSID 9.
How so? CLOSID 9 is using CLOSID 1 L2 settings. Are we just keeping the L2
setting of CLOSID 1 around and do not reset it to default?
> When you make a new directory that gets allocated CLOSID 1, it will have
> both L3 and L2 lines.
Now CLOSID 1 is reused and reset to all 1's per default and even if not
then the operator will set a new L2 value and therefor wreckaging CLOSID 9.