On Thu, Oct 19, 2017 at 08:33:23AM +0530, Vinod Koul wrote:

> + *  BSD LICENSE
> + *
> + *  Copyright(c) 2015-17 Intel Corporation.
> + *
> + *  Redistribution and use in source and binary forms, with or without
> + *  modification, are permitted provided that the following conditions
> + *  are met:

Really unhappy with the dual licensing for regmap code, this is
interface code for some GPL only kernel code and...

> +static int regmap_sdw_write(void *context, unsigned int reg, unsigned int 
> val)
> +{
> +     struct device *dev = context;
> +     struct sdw_slave *slave = dev_to_sdw_dev(dev);
> +
> +     /* Check for Slave */
> +     if (!slave)
> +             return 0;

We silently ignore the device not existing?

> +static struct regmap_bus regmap_sdw = {
> +     .reg_read = regmap_sdw_read,
> +     .reg_write = regmap_sdw_write,

Given that the bus appears to support bulk operations why are we
implementing this with reg_read() and reg_write()?  

> +             return ERR_PTR(ret);
> +
> +     return __regmap_init(&sdw->dev, &regmap_sdw,
> +                     &sdw->dev, config, lock_key, lock_name);
> +}
> +EXPORT_SYMBOL(__regmap_init_sdw);

...this is just an obvious attempt to allow non-GPL code to directly use
GPL code.

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