On Mon, Nov 6, 2017 at 3:31 PM, Oleg Nesterov <o...@redhat.com> wrote:
> On 11/06, Jamie Iles wrote:
>>
>> I'm unable to reproduce the warning in qemu with SMP (on a 32 CPU VM).
>
> Neither me. Perhaps because I tried this test-case on the minimal system
> with /bin/sh running as init process.
>
>> Instead I get the following instant traceback which is different to what
>> you report when run as root:
>>
>> [   45.018469] Kernel panic - not syncing: Attempted to kill init! 
>> exitcode=0x00000013
>> [   45.018469]
>> [   45.019669] CPU: 19 PID: 1 Comm: systemd Not tainted 4.14.0-rc8 #7
>> [   45.021094] Hardware name: QEMU Standard PC (i440FX + PIIX, 1996), BIOS 
>> 1.10.1-1ubuntu1 04/01/2014
>> [   45.022768] Call Trace:
>> [   45.023076]  dump_stack+0x12e/0x188
>> [   45.023481]  panic+0x1e4/0x417
>
> This is fine and hopefully confirms the theory. let me quote my previous 
> email:
>
>                 line 111    r[8] = syscall(__NR_ptrace, 0x10ul, r[7]);
>
>         this is PTRACE_ATTACH
>
>                 line 115        syscall(__NR_ptrace, 0x4200ul, r[7], 
> 0x40000012ul, 0x100012ul);
>
>         this is PTRACE_SETOPTIONS and "data" includes PTRACE_O_EXITKILL.
>
>         r[7] is initialized at
>
>                 line 110      r[7] = *(uint32_t*)0x20f9cffc;
>
>         so if it is eq to 1 then it can attach to init and in this case the 
> problem
>         can be explained by the wrong SIGNAL_UNKILLABLE/SIGKILL logic.
>
> So, if it is eq to 1 then init will be killed after the child process created
> by loop() function exits (see PTRACE_O_EXITKILL above).
>
> This is correct, only the warning is not.
>
> For example, this command does ptrace(PTRACE_SEIZE, 1,0, PTRACE_O_EXITKILL)
>
>         # perl -e 'syscall 101, 0x4206, 1, 0, 0x100000'
>
> and crashes the kernel the same way, this is correct.


Oleg, I've tested the patch and I don't see the WARNING with it. Only
attempt to kill init, which is fine, we test inside of pid namespace
and test process is not able to reach init.

Tested-by: Dmitry Vyukov <dvyu...@google.com>

Reply via email to