One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct foo {
int stuff;
void *entry[];
};
instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL);
Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:
instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL);
Signed-off-by: Gustavo A. R. Silva <[email protected]>
---
drivers/rtc/rtc-sun6i.c | 3 +--
1 file changed, 1 insertion(+), 2 deletions(-)
diff --git a/drivers/rtc/rtc-sun6i.c b/drivers/rtc/rtc-sun6i.c
index 2cd5a7b..fe07310 100644
--- a/drivers/rtc/rtc-sun6i.c
+++ b/drivers/rtc/rtc-sun6i.c
@@ -199,8 +199,7 @@ static void __init sun6i_rtc_clk_init(struct device_node
*node)
if (!rtc)
return;
- clk_data = kzalloc(sizeof(*clk_data) + (sizeof(*clk_data->hws) * 2),
- GFP_KERNEL);
+ clk_data = kzalloc(struct_size(clk_data, hws, 2), GFP_KERNEL);
if (!clk_data) {
kfree(rtc);
return;
--
2.7.4
