Use the wrapper function for retrieving the platform data instead of
accessing dev->platform_data directly. This is a cosmetic change
to make the code simpler and enhance the readability.

Signed-off-by: Jingoo Han <jg1....@samsung.com>
---
 drivers/w1/masters/ds1wm.c |   12 ++++++------
 1 file changed, 6 insertions(+), 6 deletions(-)

diff --git a/drivers/w1/masters/ds1wm.c b/drivers/w1/masters/ds1wm.c
index 96cab6ac..a606dba 100644
--- a/drivers/w1/masters/ds1wm.c
+++ b/drivers/w1/masters/ds1wm.c
@@ -255,17 +255,17 @@ static int ds1wm_find_divisor(int gclk)
 static void ds1wm_up(struct ds1wm_data *ds1wm_data)
 {
        int divisor;
-       struct ds1wm_driver_data *plat = ds1wm_data->pdev->dev.platform_data;
+       struct device *dev = &ds1wm_data->pdev->dev;
+       struct ds1wm_driver_data *plat = dev_get_platdata(dev);
 
        if (ds1wm_data->cell->enable)
                ds1wm_data->cell->enable(ds1wm_data->pdev);
 
        divisor = ds1wm_find_divisor(plat->clock_rate);
-       dev_dbg(&ds1wm_data->pdev->dev,
-               "found divisor 0x%x for clock %d\n", divisor, plat->clock_rate);
+       dev_dbg(dev, "found divisor 0x%x for clock %d\n",
+               divisor, plat->clock_rate);
        if (divisor == 0) {
-               dev_err(&ds1wm_data->pdev->dev,
-                       "no suitable divisor for %dHz clock\n",
+               dev_err(dev, "no suitable divisor for %dHz clock\n",
                        plat->clock_rate);
                return;
        }
@@ -481,7 +481,7 @@ static int ds1wm_probe(struct platform_device *pdev)
        ds1wm_data->cell = mfd_get_cell(pdev);
        if (!ds1wm_data->cell)
                return -ENODEV;
-       plat = pdev->dev.platform_data;
+       plat = dev_get_platdata(&pdev->dev);
        if (!plat)
                return -ENODEV;
 
-- 
1.7.10.4


--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majord...@vger.kernel.org
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/

Reply via email to