On 05/02/2014 15:48, Gregory CLEMENT wrote:
> Hi Boris,
> 
> On 05/02/2014 10:48, Boris BREZILLON wrote:
>> The parent dependency check is only available on the first parent of a given
>> clk.
>>
>> Add support for strict dependency check: all parents of a given clk must be
>> initialized.
>>
>> Signed-off-by: Boris BREZILLON <[email protected]>
>> ---
>>
>> Hello Gregory,
>>
>> This patch adds support for strict check on clk dependencies (check if all
>> parents specified by an DT clk node are initialized).
>>
>> I'm not sure this is what you were expecting (maybe testing the first parent
>> is what you really want), so please feel free to tell me if I'm wrong.
>>
>> Best Regards,
>>
>> Boris
>>
>>  drivers/clk/clk.c |   27 +++++++++++++++++++++------
>>  1 file changed, 21 insertions(+), 6 deletions(-)
>>
>> diff --git a/drivers/clk/clk.c b/drivers/clk/clk.c
>> index beb0f8b..6849769 100644
>> --- a/drivers/clk/clk.c
>> +++ b/drivers/clk/clk.c
>> @@ -2543,22 +2543,37 @@ static int parent_ready(struct device_node *np)
>>  {
>>      struct of_phandle_args clkspec;
>>      struct of_clk_provider *provider;
>> +    int num_parents;
>> +    bool found;
>> +    int i;
>>  
>>      /*
>>       * If there is no clock parent, no need to wait for them, then
>>       * we can consider their absence as being ready
>>       */
>> -    if (of_parse_phandle_with_args(np, "clocks", "#clock-cells", 0,
>> -                                    &clkspec))
>> +    num_parents = of_count_phandle_with_args(np, "clocks", "#clock-cells");
>> +    if (num_parents <= 0)
>>              return 1;
>>  
>> -    /* Check if we have such a provider in our array */
>> -    list_for_each_entry(provider, &of_clk_providers, link) {
>> -            if (provider->node == clkspec.np)
>> +    for (i = 0; i < num_parents; i++) {
>> +            if (of_parse_phandle_with_args(np, "clocks", "#clock-cells", i,
>> +                                           &clkspec))
>>                      return 1;
>> +
>> +            /* Check if we have such a provider in our array */
>> +            found = false;
>> +            list_for_each_entry(provider, &of_clk_providers, link) {
>> +                    if (provider->node == clkspec.np) {
>> +                            found = true;
>> +                            break;
> 
> Hum this means that as soon as you have one parent then you consider it
> as ready. It is better of what I have done because I only test the 1st
> parent. However I wondered if we should go further by ensuring all the
> parents are ready.

My bad, I read the code too fast. Your code already checks that all the
parents are ready.

So if you agree I will merge your code with mine and send a new patch.

> 
> If I am right, there is more than one parent only for the muxer. In this
> case is it really expected that all the parent are ready?
> 
> Thanks,
> 
> Gregory
> 
>> +                    }
>> +            }
>> +
>> +            if (!found)
>> +                    return 0;
>>      }
>>  
>> -    return 0;
>> +    return 1;
>>  }
>>  
>>  /**
>>
> 
> 


-- 
Gregory Clement, Free Electrons
Kernel, drivers, real-time and embedded Linux
development, consulting, training and support.
http://free-electrons.com
--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to [email protected]
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/

Reply via email to