Il 03/06/2014 15:06, Michael Tokarev ha scritto:
03.06.2014 16:04, Paolo Bonzini wrote:
Il 01/06/2014 01:05, Rickard Strandqvist ha scritto:
There is a risk that the variable will be used without being initialized.
This was largely found by using a static code analysis program called cppcheck.
Signed-off-by: Rickard Strandqvist <rickard_strandqv...@spectrumdigital.se>
No, there isn't. The full context looks like this:
longmode = is_long_mode(vcpu) && cs_l == 1;
if (!longmode) {
param = ((u64)kvm_register_read(vcpu, VCPU_REGS_RDX) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RAX) & 0xffffffff);
ingpa = ((u64)kvm_register_read(vcpu, VCPU_REGS_RBX) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RCX) & 0xffffffff);
outgpa = ((u64)kvm_register_read(vcpu, VCPU_REGS_RDI) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RSI) & 0xffffffff);
}
#ifdef CONFIG_X86_64
else {
param = kvm_register_read(vcpu, VCPU_REGS_RCX);
ingpa = kvm_register_read(vcpu, VCPU_REGS_RDX);
outgpa = kvm_register_read(vcpu, VCPU_REGS_R8);
}
#endif
and longmode must be zero if !CONFIG_X86_64:
This is not the first time this code is attempted to be changed.
Maybe adding an additional #ifdef..endif around the longmode
assignment and the "if" above will solve this for good?
Or maybe something like this:
#ifdef CONFIG_X86_64
if (!(is_long_mode(vcpu) && cs_l == 1)) {
#else
if (1) {
#endif
param = ((u64)kvm_register_read(vcpu, VCPU_REGS_RDX) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RAX) & 0xffffffff);
ingpa = ((u64)kvm_register_read(vcpu, VCPU_REGS_RBX) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RCX) & 0xffffffff);
outgpa = ((u64)kvm_register_read(vcpu, VCPU_REGS_RDI) << 32) |
(kvm_register_read(vcpu, VCPU_REGS_RSI) & 0xffffffff);
}
else {
param = kvm_register_read(vcpu, VCPU_REGS_RCX);
ingpa = kvm_register_read(vcpu, VCPU_REGS_RDX);
outgpa = kvm_register_read(vcpu, VCPU_REGS_R8);
}
, to make it all explicit and obvious?
... and ugly too.
If the first person who got the answer had reported a bug against
cppcheck, this perhaps would have been avoided.
Paolo
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