(Sorry, I missed the "reply to" notice. Let's try this again.) Dear Gong BingXin,
Did you check in /proc/bus/usb/devices to see if your Gamma-Ray Microscope was recognized? You should see an entry similar to the one below: T: Bus=01 Lev=02 Prnt=02 Port=00 Cnt=01 Dev#= 3 Spd=1.5 MxCh= 0 D: Ver= 2.00 Cls=00(>ifc ) Sub=00 Prot=00 MxPS= 8 #Cfgs= 1 P: Vendor=076d ProdID=c00e Rev=14.1 S: Manufacturer=PRINCETON GAMMA-TECH S: Product=PGT IGW5021-14 USB Well Detector C:* #Ifs= 1 Cfg#= 1 Atr=a0 MxPwr= 98mA I: If#= 0 Alt= 0 #EPs= 1 Cls=03(HID ) Sub=01 Prot=02 Driver=hid E: Ad=81(I) Atr=03(Int.) MxPS= 4 Ivl=10ms Best of luck, --John > please reply to [EMAIL PROTECTED] > thank you. > > > THE UNCERTAINTY PRINCIPLE IS UNTENABLE > > > By re-analysing Heisenberg's Gamma-Ray Microscope experiment and the ideal > experiment from which the uncertainty principle is derived, it is actually found > that the uncertainty principle can not be obtained from them. It is therefore found > to be untenable. > > Key words: > uncertainty principle; Heisenberg's Gamma-Ray Microscope Experiment; ideal > experiment > > Ideal Experiment 1 > > Heisenberg's Gamma-Ray Microscope Experiment > > > A free electron sits directly beneath the center of the microscope's lens (please > see AIP page http://www.aip.org/history/heisenberg/p08b.htm or diagram below) . The > circular lens forms a cone of angle 2A from the electron. The electron is then > illuminated from the left by gamma rays--high energy light which has the shortest > wavelength. These yield the highest resolution, for according to a principle of wave > optics, the microscope can resolve (that is, "see" or distinguish) objects to a size > of dx, which is related to and to the wavelength L of the gamma ray, by the > expression: > > dx = L/(2sinA) (1) > > However, in quantum mechanics, where a light wave can act like a particle, a gamma > ray striking an electron gives it a kick. At the moment the light is diffracted by > the electron into the microscope lens, the electron is thrust to the right. To be > observed by the microscope, the gamma ray must be scattered into any angle within > the cone of angle 2A. In quantum mechanics, the gamma ray carries momentum as if it > were a particle. The total momentum p is related to the wavelength by the formula, > > p = h / L, where h is Planck's constant. (2) > > In the extreme case of diffraction of the gamma ray to the right edge of the lens, > the total momentum would be the sum of the electron's momentum P'x in the x > direction and the gamma ray's momentum in the x direction: > > P' x + (h sinA) / L', where L' is the wavelength of the deflected gamma ray. > > In the other extreme, the observed gamma ray recoils backward, just hitting the left > edge of the lens. In this case, the total momentum in the x direction is: > > P''x - (h sinA) / L''. > > The final x momentum in each case must equal the initial x momentum, since momentum > is conserved. Therefore, the final x momenta are equal to each other: > > P'x + (h sinA) / L' = P''x - (h sinA) / L'' (3) > > If A is small, then the wavelengths are approximately the same, > > L' ~ L" ~ L. So we have > > P''x - P'x = dPx ~ 2h sinA / L (4) > > Since dx = L/(2 sinA), we obtain a reciprocal relationship between the minimum > uncertainty in the measured position, dx, of the electron along the x axis and the > uncertainty in its momentum, dPx, in the x direction: > > dPx ~ h / dx or dPx dx ~ h. (5) > > For more than minimum uncertainty, the "greater than" sign may added. > > Except for the factor of 4pi and an equal sign, this is Heisenberg's uncertainty > relation for the simultaneous measurement of the position and momentum of an object. > > Re-analysis > > To be seen by the microscope, the gamma ray must be scattered into any angle within > the cone of angle 2A. > > The microscope can resolve (that is, "see" or distinguish) objects to a size of dx, > which is related to and to the wavelength L of the gamma ray, by the expression: > > dx = L/(2sinA) (1) > > This is the resolving limit of the microscope and it is the uncertain quantity of > the object's position. > > The microscope can not see the object whose size is smaller than its resolving > limit, dx. Therefore, to be seen by the microscope, the size of the electron must be > larger than or equal to the resolving limit. > > But if the size of the electron is larger than or equal to the resolving limit dx, > the electron will not be in the range dx. Therefore, dx can not be deemed to be the > uncertain quantity of the electron's position which can be seen by the microscope, > but deemed to be the uncertain quantity of the electron's position which can not be > seen by the microscope. To repeat, dx is uncertainty in the electron's position > which can not be seen by the microscope. > > To be seen by the microscope, the gamma ray must be scattered into any angle within > the cone of angle 2A, so we can measure the momentum of the electron. > > dPx is the uncertainty in the electron's momentum which can be seen by microscope. > > What relates to dx is the electron where the size is smaller than the resolving > limit. When the electron is in the range dx, it can not be seen by the microscope, > so its position is uncertain. > > What relates to dPx is the electron where the size is larger than or equal to the > resolving limit .The electron is not in the range dx, so it can be seen by the > microscope and its position is certain. > > Therefore, the electron which relates to dx and dPx respectively is not the same. > What we can see is the electron where the size is larger than or equal to the > resolving limit dx and has a certain position, dx = 0. > > Quantum mechanics does not rely on the size of the object, but on Heisenberg's > Gamma-Ray Microscope experiment. The use of the microscope must relate to the size > of the object. The size of the object which can be seen by the microscope must be > larger than or equal to the resolving limit dx of the microscope, thus the uncertain > quantity of the electron's position does not exist. The gamma ray which is > diffracted by the electron can be scattered into any angle within the cone of angle > 2A, where we can measure the momentum of the electron. > > What we can see is the electron which has a certain position, dx = 0, so that in no > other position can we measure the momentum of the electron. In Quantum mechanics, > the momentum of the electron can be measured accurately when we measure the momentum > of the electron only, therefore, we have gained dPx = 0. > > And, > > dPx dx =0. (6) > > Ideal experiment 2 > > Single Slit Diffraction Experiment > > > Suppose a particle moves in the Y direction originally and then passes a slit with > width dx(Please see diagram below) . The uncertain quantity of the particle's > position in the X direction is dx, and interference occurs at the back slit . > According to Wave Optics , the angle where No.1 min of interference pattern is can > be calculated by following formula: > > sinA=L/2dx (1) > > and L=h/p where h is Planck's constant. (2) > > So the uncertainty principle can be obtained > > dPx dx ~ h (5) > > Re-analysis > > According to Newton first law , if an external force in the X direction does not > affect the particle, it will move in a uniform straight line, ( Motion State or > Static State) , and the motion in the Y direction is unchanged .Therefore , we can > learn its position in the slit from its starting point. > > The particle can have a certain position in the slit and the uncertain quantity of > the position is dx =0. According to Newton first law , if the external force at the > X direction does not affect particle, and the original motion in the Y direction is > not changed , the momentum of the particle int the X direction will be Px=0 and the > uncertain quantity of the momentum will be dPx =0. > > This gives: > > dPx dx =0. (6) > > No experiment negates NEWTON FIRST LAW. Whether in quantum mechanics or classical > mechanics, it applies to the microcosmic world and is of the form of the > Energy-Momentum conservation laws. If an external force does not affect the particle > and it does not remain static or in uniform motion, it has disobeyed the > Energy-Momentum conservation laws. Under the above ideal experiment , it is > considered that the width of the slit is the uncertain quantity of the particle's > position. But there is certainly no reason for us to consider that the particle in > the above experiment has an uncertain position, and no reason for us to consider > that the slit's width is the uncertain quantity of the particle. Therefore, the > uncertainty principle, > > dPx dx ~ h (5) > > which is derived from the above experiment is unreasonable. > > Conclusion > > > >From the above re-analysis , it is realized that the ideal experiment demonstration > >for the uncertainty principle is untenable. Therefore, the uncertainty principle is > >untenable. > > > > Reference: > 1. Max Jammer. (1974) The philosophy of quantum mechanics (John wiley & sons , Inc > New York ) Page 65 > 2. Ibid, Page 67 > 3. http://www.aip.org/history/heisenberg/p08b.htm > > > > Author : Gong BingXin > Postal address : P.O.Box A111 YongFa XiaoQu XinHua HuaDu > GuangZhou 510800 P.R.China > > E-mail: [EMAIL PROTECTED] > Tel: 86---20---86856616 > > > > ------------------------------------------------------- > This SF.net email is sponsored by: > The Definitive IT and Networking Event. Be There! > NetWorld+Interop Las Vegas 2003 -- Register today! > http://ads.sourceforge.net/cgi-bin/redirect.pl?keyn0001en > _______________________________________________ > [EMAIL PROTECTED] > To unsubscribe, use the last form field at: > https://lists.sourceforge.net/lists/listinfo/linux-usb-users ------------------------------------------------------- This SF.net email is sponsored by: The Definitive IT and Networking Event. Be There! 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