Dear Dr.Klingler,

Thank you for your message.

About the heisenberg uncertainty principle please see AIP page:
http://www.aip.org/history/heisenberg/p08b.htm

Best regards,

Gong


----- Original Message -----
From: "John Klingler" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, March 27, 2003 3:32 AM
Subject: Re: [Linux-usb-users] The Uncertainty Principle Is Untenable


> (Sorry, I missed the "reply to" notice. Let's try this again.)
>
> Dear Gong BingXin,
>
> Did you check in /proc/bus/usb/devices to see if your
> Gamma-Ray Microscope was recognized? You should see an
> entry similar to the one below:
>
> T:  Bus=01 Lev=02 Prnt=02 Port=00 Cnt=01 Dev#=  3 Spd=1.5 MxCh= 0
> D:  Ver= 2.00 Cls=00(>ifc ) Sub=00 Prot=00 MxPS= 8 #Cfgs=  1
> P:  Vendor=076d ProdID=c00e Rev=14.1
> S:  Manufacturer=PRINCETON GAMMA-TECH
> S:  Product=PGT IGW5021-14 USB Well Detector
> C:* #Ifs= 1 Cfg#= 1 Atr=a0 MxPwr= 98mA
> I:  If#= 0 Alt= 0 #EPs= 1 Cls=03(HID  ) Sub=01 Prot=02 Driver=hid
> E:  Ad=81(I) Atr=03(Int.) MxPS=   4 Ivl=10ms
>
> Best of luck,
>
> --John
>
> > please reply to [EMAIL PROTECTED]
> > thank you.
> >
> >
> > THE UNCERTAINTY PRINCIPLE IS UNTENABLE
> >
> >
> > By re-analysing Heisenberg's Gamma-Ray Microscope experiment and the
ideal experiment from which the uncertainty principle is derived, it is
actually found that the uncertainty principle can not be obtained from them.
It is therefore found to be untenable.
> >
> > Key words:
> > uncertainty principle; Heisenberg's Gamma-Ray Microscope Experiment;
ideal experiment
> >
> > Ideal Experiment 1
> >
> >                  Heisenberg's Gamma-Ray Microscope Experiment
> >
> >
> > A free electron sits directly beneath the center of the microscope's
lens (please see AIP page http://www.aip.org/history/heisenberg/p08b.htm or
diagram below) . The circular lens forms a cone of angle 2A from the
electron. The electron is then illuminated from the left by gamma rays--high
energy light which has the shortest wavelength. These yield the highest
resolution, for according to a principle of wave optics, the microscope can
resolve (that is, "see" or distinguish) objects to a size of dx, which is
related to and to the wavelength L of the gamma ray, by the expression:
> >
> > dx = L/(2sinA) (1)
> >
> > However, in quantum mechanics, where a light wave can act like a
particle, a gamma ray striking an electron gives it a kick. At the moment
the light is diffracted by the electron into the microscope lens, the
electron is thrust to the right. To be observed by the microscope, the gamma
ray must be scattered into any angle within the cone of angle 2A. In quantum
mechanics, the gamma ray carries momentum as if it were a particle. The
total momentum p is related to the wavelength by the formula,
> >
> > p = h / L, where h is Planck's constant. (2)
> >
> > In the extreme case of diffraction of the gamma ray to the right edge of
the lens, the total momentum would be the sum of the electron's momentum P'x
in the x direction and the gamma ray's momentum in the x direction:
> >
> > P' x + (h sinA) / L', where L' is the wavelength of the deflected gamma
ray.
> >
> > In the other extreme, the observed gamma ray recoils backward, just
hitting the left edge of the lens. In this case, the total momentum in the x
direction is:
> >
> > P''x - (h sinA) / L''.
> >
> > The final x momentum in each case must equal the initial x momentum,
since momentum is conserved. Therefore, the final x momenta are equal to
each other:
> >
> > P'x + (h sinA) / L' = P''x - (h sinA) / L'' (3)
> >
> > If A is small, then the wavelengths are approximately the same,
> >
> > L' ~ L" ~ L. So we have
> >
> > P''x - P'x = dPx ~ 2h sinA / L (4)
> >
> > Since dx = L/(2 sinA), we obtain a reciprocal relationship between the
minimum uncertainty in the measured position, dx, of the electron along the
x axis and the uncertainty in its momentum, dPx, in the x direction:
> >
> > dPx ~ h / dx or dPx dx ~ h. (5)
> >
> > For more than minimum uncertainty, the "greater than" sign may added.
> >
> > Except for the factor of 4pi and an equal sign, this is Heisenberg's
uncertainty relation for the simultaneous measurement of the position and
momentum of an object.
> >
> > Re-analysis
> >
> > To be seen by the microscope, the gamma ray must be scattered into any
angle within the cone of angle 2A.
> >
> > The microscope can resolve (that is, "see" or distinguish) objects to a
size of dx, which is related to and to the wavelength L of the gamma ray, by
the expression:
> >
> > dx = L/(2sinA) (1)
> >
> > This is the resolving limit of the microscope and it is the uncertain
quantity of the object's position.
> >
> > The microscope can not see the object whose size is smaller than its
resolving limit, dx. Therefore, to be seen by the microscope, the size of
the electron must be larger than or equal to the resolving limit.
> >
> > But if the size of the electron is larger than or equal to the resolving
limit dx, the electron will not be in the range dx. Therefore, dx can not be
deemed to be the uncertain quantity of the electron's position which can be
seen by the microscope, but deemed to be the uncertain quantity of the
electron's position which can not be seen by the microscope. To repeat, dx
is uncertainty in the electron's position which can not be seen by the
microscope.
> >
> > To be seen by the microscope, the gamma ray must be scattered into any
angle within the cone of angle 2A, so we can measure the momentum of the
electron.
> >
> > dPx is the uncertainty in the electron's momentum which can be seen by
microscope.
> >
> > What relates to dx is the electron where the size is smaller than the
resolving limit. When the electron is in the range dx, it can not be seen by
the microscope, so its position is uncertain.
> >
> > What relates to dPx is the electron where the size is larger than or
equal to the resolving limit .The electron is not in the range dx, so it can
be seen by the microscope and its position is certain.
> >
> > Therefore, the electron which relates to dx and dPx respectively is not
the same. What we can see is the electron where the size is larger than or
equal to the resolving limit dx and has a certain position, dx = 0.
> >
> > Quantum mechanics does not rely on the size of the object, but on
Heisenberg's Gamma-Ray Microscope experiment. The use of the microscope must
relate to the size of the object. The size of the object which can be seen
by the microscope must be larger than or equal to the resolving limit dx of
the microscope, thus the uncertain quantity of the electron's position does
not exist. The gamma ray which is diffracted by the electron can be
scattered into any angle within the cone of angle 2A, where we can measure
the momentum of the electron.
> >
> > What we can see is the electron which has a certain position, dx = 0, so
that in no other position can we measure the momentum of the electron. In
Quantum mechanics, the momentum of the electron can be measured accurately
when we measure the momentum of the electron only, therefore, we have gained
dPx = 0.
> >
> > And,
> >
> > dPx dx =0. (6)
> >
> > Ideal experiment 2
> >
> > Single Slit Diffraction Experiment
> >
> >
> > Suppose a particle moves in the Y direction originally and then passes a
slit with width dx(Please see diagram below) . The uncertain quantity of the
particle's position in the X direction is dx, and interference occurs at the
back slit . According to Wave Optics , the angle where No.1 min of
interference pattern is can be calculated by following formula:
> >
> > sinA=L/2dx (1)
> >
> > and L=h/p where h is Planck's constant. (2)
> >
> > So the uncertainty principle can be obtained
> >
> > dPx dx ~ h (5)
> >
> > Re-analysis
> >
> > According to Newton first law , if an external force in the X direction
does not affect the particle, it will move in a uniform straight line, (
Motion State or Static State) , and the motion in the Y direction is
unchanged .Therefore , we can learn its position in the slit from its
starting point.
> >
> > The particle can have a certain position in the slit and the uncertain
quantity of the position is dx =0. According to Newton first law , if the
external force at the X direction does not affect particle, and the original
motion in the Y direction is not changed , the momentum of the particle int
the X direction will be Px=0 and the uncertain quantity of the momentum will
be dPx =0.
> >
> > This gives:
> >
> > dPx dx =0. (6)
> >
> > No experiment negates NEWTON FIRST LAW. Whether in quantum mechanics or
classical mechanics, it applies to the microcosmic world and is of the form
of the Energy-Momentum conservation laws. If an external force does not
affect the particle and it does not remain static or in uniform motion, it
has disobeyed the Energy-Momentum conservation laws. Under the above ideal
experiment , it is considered that the width of the slit is the uncertain
quantity of the particle's position. But there is certainly no reason for us
to consider that the particle in the above experiment has an uncertain
position, and no reason for us to consider that the slit's width is the
uncertain quantity of the particle. Therefore, the uncertainty principle,
> >
> > dPx dx ~ h (5)
> >
> > which is derived from the above experiment is unreasonable.
> >
> > Conclusion
> >
> >
> > >From the above re-analysis , it is realized that the ideal experiment
demonstration for the uncertainty principle is untenable. Therefore, the
uncertainty principle is untenable.
> >
> >
> >
> > Reference:
> > 1. Max Jammer. (1974) The philosophy of quantum mechanics (John wiley &
sons , Inc New York ) Page 65
> > 2. Ibid, Page 67
> > 3. http://www.aip.org/history/heisenberg/p08b.htm
> >
> >
> >
> > Author : Gong BingXin
> > Postal address : P.O.Box A111 YongFa XiaoQu XinHua HuaDu
> >                GuangZhou 510800 P.R.China
> >
> > E-mail: [EMAIL PROTECTED]
> > Tel: 86---20---86856616
> >
> >
> >
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