On Thu, 2018-08-30 at 10:31 +0200, Lorenzo Bianconi wrote:

> Reviewing the code I guess it is not necessary since pskb_expand_head routine
> does not modify head->len (or skb->len). 

True.

> Packet len (if we consider padding) is only modified in:
> 
> memset(skb_push(skb, pad), 0, pad);
> 
> and if we hit that point, we will account new skb->len in flow backlog. Do you
> agree?

Right, but that's the *pad*. I was thinking about the header conversion.

Let's say you decided to add the second frame to the A-MSDU, at which
point the first one isn't really an A-MSDU yet. So we get to:

        if (!ieee80211_amsdu_prepare_head(sdata, fast_tx, head))

which changes the header of "head" to be 14 bytes longer:

        skb_push(skb, sizeof(*amsdu_hdr));

But now let's say we get a failure here when reallocating the second
subframe:

        if (!ieee80211_amsdu_realloc_pad(local, skb, sizeof(rfc1042_header) +
                                                     2 + pad))
                goto out;

Now we have changed "head", which is on the FQ, but we haven't changed
the FQ accounting. So I *think* we still need this:

--- a/net/mac80211/tx.c
+++ b/net/mac80211/tx.c
@@ -3239,7 +3239,7 @@ static bool ieee80211_amsdu_aggregate(struct 
ieee80211_sub_if_data *sdata,
 
        if (!ieee80211_amsdu_realloc_pad(local, skb, sizeof(rfc1042_header) +
                                                     2 + pad))
-               goto out;
+               goto out_recalc;
 
        ret = true;
        data = skb_push(skb, ETH_ALEN + 2);
@@ -3256,11 +3256,13 @@ static bool ieee80211_amsdu_aggregate(struct 
ieee80211_sub_if_data *sdata,
        head->data_len += skb->len;
        *frag_tail = skb;
 
-       flow->backlog += head->len - orig_len;
-       tin->backlog_bytes += head->len - orig_len;
-
-       fq_recalc_backlog(fq, tin, flow);
+out_recalc:
+       if (head->len != orig_len) {
+               flow->backlog += head->len - orig_len;
+               tin->backlog_bytes += head->len - orig_len;
 
+               fq_recalc_backlog(fq, tin, flow);
+       }
 out:
        spin_unlock_bh(&fq->lock);
 


> Looking at the code maybe I spotted another issue, I guess there is an
> off-by-one issue in 'n' estimation since it does not take into account
> the first frame. We hit the line:
> 
> while (*frag_tail) {
> }
> 
> starting from the second subframe, but if the head does not have packet in the
> fraglist we will end up having n = 1, while it is actually the second frame.

Hmm, not sure I follow? "head" is the A-MSDU, containing the A-MSDU
header and the first subframe in skb->data (and/or frags), with the
subframes 2..N in the fraglist.

So I think this is right?

johannes

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