How does the fallback version get executed? Stepping through the reset sequence it looks from my image that that's the default.

Jordan

At 02:52 PM 11/18/2003, ron minnich wrote:
On Tue, 18 Nov 2003, Jordan Archer wrote:

> I'm pretty sure that it's not 32 bit reset code.  The problem appears if I
> try to build an image without a fallback.

oh. When I try to build an image without a fallback (this part is
counterintuitive) I always just build a fallback. Possibly that's the
wrong thing to do :0)

ron

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