Segher Boessenkool wrote: >>> Surely there is something called something like of_node_is_compatible() >>> you can use here? You already have the node pointer, there is no need >>> to look at all other nodes. >>> >> >> I see the point. >> I didn't find of_node_is_compatible() but I'll look what's available >> here. > > int of_device_is_compatible(const struct device_node *device, > const char *compat) >
Thanks. I'll pick that. Cheers, Albert _______________________________________________ Linuxppc-dev mailing list Linuxppc-dev@lists.ozlabs.org https://lists.ozlabs.org/listinfo/linuxppc-dev
