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How about this for a simple approach? Simply
respect REBOL's insistence on passing by value and
work with it;
>> inc: func[x][x + 1]
>> a: 0
==
0
>> a: inc a ; all one has to do is insert a: , not even one extra
line of code!
== 1
>> a
== 1 ; a has been incremented as
intended and the script is much clearer!
>>
----- Original Message -----
Sent: Thursday, December 16, 1999 10:50
AM
Subject: [REBOL] Passing by reference
Re:(3)
Perhaps this will make more sense to you:
>> a: 0
== 0
>> b: to-set-word 'a
== a:
>> ; Note the ":"
>> b 1
== 1
>> a
== 1
On Thu, 16 Dec 1999 15:39:51 +0000, [EMAIL PROTECTED] wrote:
>Hi Anton,
>
>Hmmm.
So why doesn't:
>
> to-set-word b 1
>
>work then? What is the difference when you assign
"to-set-word b" to another
>word (c) and then use c? Why
does your method work whereas mine doesn't?
>
>> > Passing by reference
>>
>> > a: 0
; >> 0
>> > b: 'a
; >> a
>> > to-set-word b
; >> a:
>> > to-set-word b 1 ; >>
1
>> > a
; >> 0
>> >
>> > so what is the
point of to-set-word if I can then not use it to set the
>>
> thing? Do I need an extra block and a "do" or something like that?
>>
>> c: to-set-word b
>> c 1
>>
a ; >> 1
>>
>> Regards
>> --
>>
>> Anton
>>
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Chris
Mahnken
[EMAIL PROTECTED]
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