Hello [EMAIL PROTECTED]!
On 18-Set-00, you wrote:
j> Read through the colon-delimited file below (a copy of
j> an /etc/passwd file, mangled for security purposes),
j> and print a report tallying the distinct values in the
j> 7th field (in this case, the field that identifies the
j> default shell for each userID). Sort the results by
j> the value of the field being tallied, and print the
j> results in neat columns.
This uses a /DIRECT port; it's a bit different,too, just to show
another way to do it. :)
========================================================
REBOL []
foreach-line: func [
file [file!]
code [block!]
/local line
] [
; I don't know if this REALLY uses less memory...
file: open/read/direct/lines file
code: func [line] code
while [line: pick file 1] [code line]
close file
]
shells: []
count-shell: func [shell [string! none!]] [
change shell: any [
find/tail shells shell
insert tail shells shell
] 1 + any [shell/1 0]
]
foreach-line %passwords.txt [
count-shell pick parse/all line ":" 7
]
foreach [shell count] sort/skip shells 2 [
print [
; we really need FORMAT here!
head insert/dup count: form count " " 3 - length? count
any [shell "(none)"]
]
]
========================================================
I don't have Perl here, so please repeat the tests with this to
see if it makes any difference.
Regards,
Gabriele.
--
Gabriele Santilli <[EMAIL PROTECTED]> - Amigan - REBOL programmer
Amiga Group Italia sez. L'Aquila -- http://www.amyresource.it/AGI/
