I keep hearing different claims about the force in an increasing wind.
Some say it goes up to the cube, some say to the square.
Since E=M times Vsquared, and I find that people generally tend to
exaggerate to make their points seem stronger, I would put my money on the
force going up to the square of the velocity.
Norm
S/V Bandersnatch
Lying Julington Creek FL
30 07.72N 081 38.4W
> [Original Message]
> From: Arild Jensen <[EMAIL PROTECTED]>
> To: TWL2: <[EMAIL PROTECTED]>
> Date: 1/25/2008 2:19:16 PM
> Subject: (T&T: & TWL2:) Look. It's a Freighter. It's a Sailboat. It's.
Both
>
>
>
>
> > -----Original Message-----
> > (SNIP) However the theory is that being a kite it can get up to a higher
> > altitude where wind speeds can be consistently over 50 knots, and even
> higher they
> > can often be found at 100 knots or more. So this small sail would have
to
> > be very tough and have a long line,
>
>
> Wind force increases according to the cube rule.
> Double the wind speed and the force increases by cube. 2 x 2 X 2 = 8
> Therefore doubling the wind speed increases the force 8 times.
>
> A sailboat spinnaker is fairly close to the sea surface. A kite 100 - 200
> feet up can well experience wind speeds twice as fast. That means the same
> sail will deliver 8 times the pulling force compared to having it close to
> sea surface.
>
> Yes the sail has to be very strong. But we routinely use parachutes to
brake
> returning space shuttles, arrest landing jet air craft and air drop
> complete tanks and other cargo. It not exactly experimental technology.
> Cheers
> Arild
>
>
>
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