jasonmolenda added inline comments.

================
Comment at: lldb/source/Target/Process.cpp:5569-5570
+
+  if (m_code_address_mask == 0)
+    return -1; // All bits are used for addressing.
+
----------------
pcc wrote:
> JDevlieghere wrote:
> > jasonmolenda wrote:
> > > pcc wrote:
> > > > Is this part correct? (Same below.) In D100521 you have
> > > > ```
> > > >   if (pc & pac_sign_extension)
> > > >     return pc | mask;
> > > >   return pc & (~mask);
> > > > ```
> > > > So it looks like this would cause the pc to be set to 0 (or -1)?
> > > I get confused so I like to do this by hand quickly to make sure I 
> > > understand.
> > > 
> > > given mask of 1110000 and addr of xxx1011 where 'x' are PAC bits,
> > > 
> > > b55 == 1: m | a == 1111011
> > > b55 == 0: ~m & a == 0001011
> > > 
> > > given mask of 1111111, low address 0001011 and high address 1111011,
> > > 
> > > b55 == 1: m & ha == ha
> > > b55 == 0: ~m | la == la
> > > 
> > > am I  not thinking of something that could unify these?  I can confuse 
> > > myself so easily with these things.
> > > 
> > > We could also detect a mask of -1 and just return the original address in 
> > > FixCodeAddress/FixDataAddress, right.  That would be very simple.
> > I've added checking for -1 in D100521
> With a mask of 1111111 isn't it
> 
> b55 == 1: m | ha == 1111111
> b55 == 0: ~m & la == 0000000
> 
> I think you can just remove lines 5569-5570 here as well as lines 819-820 
> from D100521.
urk.  my caveat that I often confuse myself with these has been proven true. :) 

So you're suggesting the default, uninitialized, mask is 0.  If we have that, 
then

mask 0, low address 0001011, high address 1111011
b55 == 1: m | ha == 1111011
b55 == 0: ~m & la == 0001011

In the mask, any bit set to 0 is passed through as-is.  Any bit set to 1 is 
going to be cleared or set in these FixAddress methods.  I see.


CHANGES SINCE LAST ACTION
  https://reviews.llvm.org/D100515/new/

https://reviews.llvm.org/D100515

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