Hi all,
May be because of the following reason io_submit returns value 1
success:
1) Uninitialized iocb structure may have some valid data (means some
time uninitialized structure would be equal to 1)
2) memory space would have to be emitted by the compiler for "iocb".
3) The contents of this memory location should be considered random.
Even in LTP code struct iocb *iocbs is first initialized with iocbs[0] =
&iocb; May some time iocbs will contain valid data which is enough for
the operation.
Should I remove iocbs[0] = &iocb; this line from the code, so
that it will be make sure that iocbs structure is properly
uninitialized.
Thanks,
Nitin Yadav
-----Original Message-----
From: [email protected] [mailto:[email protected]]
Sent: Wednesday, October 17, 2012 6:15 PM
To: Nitin Yadav
Cc: [email protected]; Jan Stancek;
[email protected]
Subject: Re: [LTP] [PATCH] io_submit: uninitialized iocb may
notreturn-EINVAL
Hi!
> When the test fails, the return value from io_submit() is 1. This
> means that io_submit successfully submitted one I/O request block for
> processing.
> Could you please let me know is it correct behavior to
successfully
> submit io request for uninitialized iocb with return value
> 1 (-EPERM).
As far as I understand io_submit() return value 1 is success i.e. 1 io
request queued. So I think that in your case the uninitialized structure
contains data valid enough for the operation to be actually queued.
--
Cyril Hrubis
[email protected]
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