------=_NextPart_001_0004_01CF029B.5B4EA1A0
Content-Type: text/plain;
        charset="us-ascii"
Content-Transfer-Encoding: 7bit

Merry Post Christmas. I finally had some time to work through the math (beat
Mathematica into submission) for the string tension and do a plot. Quite
instructive.



For the conditions of my 11th course gut C string:



Diameter = 0.00203

Density = 1360

Len = 0.685

Tension = 28.0



Which produces a pitch at 58.2 HZ.

For the Frequency as a function of Tension the equation is:





For the Cents as a function of Tension around the C string frequency the
equation is:



or

                Cents[T_] 
using the values for the C string.



For an increase in Tension of 1.0 newton (0.1 kg) the difference in pitch is
30.3744 Cents

For an decrease in Tension of 1.0 newtom (0.1kg) the different in pitch is
-31.4817 Cents



Pretty sensitive to small changes in tension.



The partial derivative of this with T_ is:

                CentsPerNewton[T_] 


This is a pretty straightforward equation. It states that the sensitivity of
the string (in cents) for the C string to Tension is inversely proportional
to the Tension. That means that if we increase the tension the change in
pitch (in cents) goes down).



The chart is:







So, higher tension strings will reduce the sensitivity. But not by a lot (if
we keep to a reasonable range). The bottom line is that the 11th course of a
baroque lute at this string length using gut is just a pain to tune. The
only reasonable choice is to provide a better tuning mechanism such as the
planetary gear tuners.



Anyway, thanks for your patience as I work through this. It has been fun and
now I think I understand what is happening.



Regards

David



-----Original Message-----
From: [email protected] [mailto:[email protected]] On Behalf
Of David van Ooijen
Sent: Friday, December 20, 2013 9:03 AM
Cc: Lute List
Subject: [LUTE] Re: Question on String Tension



   >> When I plot the partial derivative of F'(T) using the values for

   this string I find that the sensitivity is actually quite small; less

   than 1/10th of a hertz per Newton

   <<

   Don't think in Hertz. The difference between 440 and 441Hz is a smaller

   difference in pitch than between 40 and 41 Hz. Think in cents, it makes

   calculating easier, and the results are easer to understand too.

   David



   --





To get on or off this list see list information at
<http://www.cs.dartmouth.edu/~wbc/lute-admin/index.html>
http://www.cs.dartmouth.edu/~wbc/lute-admin/index.html


------=_NextPart_001_0004_01CF029B.5B4EA1A0
Content-Type: text/html;
        charset="us-ascii"
Content-Transfer-Encoding: quoted-printable

<html xmlns:v="urn:schemas-microsoft-com:vml" 
xmlns:o="urn:schemas-microsoft-com:office:office" 
xmlns:w="urn:schemas-microsoft-com:office:word" 
xmlns:m="http://schemas.microsoft.com/office/2004/12/omml"; 
xmlns="http://www.w3.org/TR/REC-html40";><head><meta http-equiv=Content-Type 
content="text/html; charset=us-ascii"><meta name=Generator content="Microsoft 
Word 15 (filtered medium)"><!--[if !mso]><style>v\:* 
{behavior:url(#default#VML);}
o\:* {behavior:url(#default#VML);}
w\:* {behavior:url(#default#VML);}
.shape {behavior:url(#default#VML);}
</style><![endif]--><style><!--
/* Font Definitions */
@font-face
        {font-family:Courier;
        panose-1:2 7 4 9 2 2 5 2 4 4;}
@font-face
        {font-family:"Cambria Math";
        panose-1:2 4 5 3 5 4 6 3 2 4;}
@font-face
        {font-family:Calibri;
        panose-1:2 15 5 2 2 2 4 3 2 4;}
/* Style Definitions */
p.MsoNormal, li.MsoNormal, div.MsoNormal
        {margin:0in;
        margin-bottom:.0001pt;
        font-size:11.0pt;
        font-family:"Calibri","sans-serif";}
a:link, span.MsoHyperlink
        {mso-style-priority:99;
        color:#0563C1;
        text-decoration:underline;}
a:visited, span.MsoHyperlinkFollowed
        {mso-style-priority:99;
        color:#954F72;
        text-decoration:underline;}
p.MsoPlainText, li.MsoPlainText, div.MsoPlainText
        {mso-style-priority:99;
        mso-style-link:"Plain Text Char";
        margin:0in;
        margin-bottom:.0001pt;
        font-size:11.0pt;
        font-family:"Calibri","sans-serif";}
span.PlainTextChar
        {mso-style-name:"Plain Text Char";
        mso-style-priority:99;
        mso-style-link:"Plain Text";
        font-family:"Calibri","sans-serif";}
span.MathematicaFormatStandardForm
        {mso-style-name:MathematicaFormatStandardForm;
        mso-style-priority:99;
        font-family:Courier;}
.MsoChpDefault
        {mso-style-type:export-only;}
@page WordSection1
        {size:8.5in 11.0in;
        margin:1.0in 1.0in 1.0in 1.0in;}
div.WordSection1
        {page:WordSection1;}
--></style><!--[if gte mso 9]><xml>
<o:shapedefaults v:ext="edit" spidmax="1026" />
</xml><![endif]--><!--[if gte mso 9]><xml>
<o:shapelayout v:ext="edit">
<o:idmap v:ext="edit" data="1" />
</o:shapelayout></xml><![endif]--></head><body lang=EN-US link="#0563C1" 
vlink="#954F72"><div class=WordSection1><p class=MsoPlainText>Merry Post 
Christmas. I finally had some time to work through the math (beat Mathematica 
into submission) for the string tension and do a plot. Quite 
instructive.<o:p></o:p></p><p class=MsoPlainText><o:p>&nbsp;</o:p></p><p 
class=MsoPlainText>For the conditions of my 11th course gut C 
string:<o:p></o:p></p><p class=MsoPlainText><o:p>&nbsp;</o:p></p><p 
class=MsoPlainText style='margin-left:.5in'>Diameter = 0.00203<o:p></o:p></p><p 
class=MsoPlainText style='margin-left:.5in'>Density = 1360<o:p></o:p></p><p 
class=MsoPlainText style='margin-left:.5in'>Len = 0.685<o:p></o:p></p><p 
class=MsoPlainText style='margin-left:.5in'>Tension = 28.0<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>Which produces a 
pitch at 58.2 HZ.<o:p></o:p></p><p class=MsoPlainText>For the Frequency as a 
function of Tension the equation is:<o:p!
 ></o:p></p><p class=MsoPlainText style='margin-left:.5in'><!--[if gte 
 >msEquation 12]><m:oMathPara><m:oMathParaPr><m:jc 
 >m:val="left"/></m:oMathParaPr><m:oMath><span style='font-family:"Cambria 
 >Math","serif"'> <m:r><m:rPr><m:scr m:val="roman"/><m:sty 
 >m:val="p"/></m:rPr>Frequency</m:r><m:r><i>[</i></m:r><m:r><m:rPr><m:scr 
 >m:val="roman"/><m:sty 
 >m:val="p"/></m:rPr>T_</m:r><m:r><i>]=</i></m:r></span><m:f><m:fPr><span 
 >style='font-family:"Cambria 
 >Math","serif"'><m:ctrlPr></m:ctrlPr></span></m:fPr><m:num><m:sSup><m:sSupPr><span
 > style='font-family:"Cambria 
 >Math","serif"'><m:ctrlPr></m:ctrlPr></span></m:sSupPr><m:e><i><span 
 >style='font-family:"Cambria 
 >Math","serif"'><m:r>(</m:r></span></i><m:f><m:fPr><span 
 >style='font-family:"Cambria 
 >Math","serif"'><m:ctrlPr></m:ctrlPr></span></m:fPr><m:num><i><span 
 >style='font-family:"Cambria 
 >Math","serif"'><m:r>T</m:r></span></i></m:num><m:den><i><span 
 >style='font-family:"Cambria Math","serif"'><m:r>&#960;</m:r></span></i><span 
 >style='font-family:"C!
 ambria Math","serif"'><m:r><m:rPr><m:scr m:val="roman"/><m:sty!
  m:val="p"/></m:rPr>Density</m:r></span></m:den></m:f><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>)</m:r></span></i></m:e><m:sup><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>0.5</m:r></span></i></m:sup></m:sSup></m:num><m:den><span 
style='font-family:"Cambria Math","serif"'><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Diameter</m:r><m:r><i>*</i></m:r><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Len</m:r></span></m:den></m:f></m:oMath></m:oMathPara><![endif]--><![if
 !msEquation]><span 
style='font-size:11.0pt;font-family:"Calibri","sans-serif";mso-fareast-language:EN-US'><img
 width=205 height=47 id="_x0000_i1025" 
src="cid:[email protected]"></span><![endif]><o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>For the Cents as 
a function of Tension around the C string frequency the equation 
is:<o:p></o:p></p><p class=MsoPlainText style='margin-left:.5in'><!--[if gte 
msEquation 12]><m!
 :oMathPara><m:oMathParaPr><m:jc m:val="left"/></m:oMathParaPr><m:oMath><span 
style='font-family:"Cambria Math","serif"'><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Cents</m:r><m:r><i>[</i></m:r><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>T_</m:r><m:r><i>]=1200.*</i></m:r><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Log</m:r><m:r><i>[2,</i></m:r></span><m:f><m:fPr><m:type 
m:val="lin"/><span style='font-family:"Cambria 
Math","serif"'><m:ctrlPr></m:ctrlPr></span></m:fPr><m:num><span 
style='font-family:"Cambria Math","serif"'><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Frequency</m:r><m:r><i>[</i></m:r><m:r><i>T</i></m:r><m:r><i>]</i></m:r></span></m:num><m:den><i><span
 style='font-family:"Cambria 
Math","serif"'><m:r>58.2168</m:r></span></i></m:den></m:f><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>]</m:r></span></i></m:oMath></m:oMathPara><![endif]--><![if 
!msEquation]><span style='font-size:11.0pt;font!
 -family:"Calibri","sans-serif";mso-fareast-language:EN-US'><img width=3!
 17 height=17 id="_x0000_i1025" 
src="cid:[email protected]"></span><![endif]><o:p></o:p></p><p 
class=MsoPlainText>or<o:p></o:p></p><p 
class=MsoPlainText>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
 Cents[T_] = <!--[if gte msEquation 12]><m:oMath><i><span 
style='font-family:"Cambria Math","serif"'><m:r>1731.23</m:r></span></i><span 
style='font-family:"Cambria Math","serif"'><m:r><m:rPr><m:scr 
m:val="roman"/><m:sty 
m:val="p"/></m:rPr>Log</m:r><m:r><i>[0.188982</i></m:r></span><m:sSup><m:sSupPr><span
 style='font-family:"Cambria 
Math","serif"'><m:ctrlPr></m:ctrlPr></span></m:sSupPr><m:e><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>T</m:r></span></i></m:e><m:sup><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>0.5</m:r></span></i></m:sup></m:sSup><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>]</m:r></span></i></m:oMath><![endif]--><![if 
!msEquation]><span style='font-size:11.0pt;font-family:!
 
"Calibri","sans-serif";position:relative;top:3.0pt;mso-text-raise:-3.0pt;mso-fareast-language:EN-US'><img
 width=169 height=18 id="_x0000_i1025" 
src="cid:[email protected]"></span><![endif]><o:p></o:p></p><p 
class=MsoPlainText>using the values for the C string.<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>For an increase 
in Tension of 1.0 newton (0.1 kg) the difference in pitch is 30.3744 
Cents<o:p></o:p></p><p class=MsoPlainText>For an decrease in Tension of 1.0 
newtom (0.1kg) the different in pitch is -31.4817 Cents<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>Pretty sensitive 
to small changes in tension.<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>The partial 
derivative of this with T_ is:<o:p></o:p></p><p 
class=MsoPlainText>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
 CentsPerNewton[T_] = <!--[if gte msEquation !
 12]><m:oMath><m:f><m:fPr><span style='font-family:"Cambria Math","serif!
 "'><m:ctrlPr></m:ctrlPr></span></m:fPr><m:num><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>865.617</m:r></span></i></m:num><m:den><i><span 
style='font-family:"Cambria 
Math","serif"'><m:r>T</m:r></span></i></m:den></m:f></m:oMath><![endif]--><![if 
!msEquation]><span 
style='font-size:11.0pt;font-family:"Calibri","sans-serif";position:relative;top:6.0pt;mso-text-raise:-6.0pt;mso-fareast-language:EN-US'><img
 width=39 height=25 id="_x0000_i1025" 
src="cid:[email protected]"></span><![endif]><o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>This is a pretty 
straightforward equation. It states that the sensitivity of the string (in 
cents) for the C string to Tension is inversely proportional to the Tension. 
That means that if we increase the tension the change in pitch (in cents) goes 
down).<o:p></o:p></p><p class=MsoPlainText><o:p>&nbsp;</o:p></p><p 
class=MsoPlainText>The chart is:<o:p></o:p></p><p class=MsoPlainText><o:p>&nbs!
 p;</o:p></p><p class=MsoPlainText><span 
class=MathematicaFormatStandardForm><img width=360 height=228 
id="Picture_x0020_3" 
src="cid:[email protected]"></span><o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText><a 
name="_MailEndCompose">So, higher tension strings will reduce the sensitivity. 
But not by a lot (if we keep to a reasonable range). The bottom line is that 
the 11<sup>th</sup> course of a baroque lute at this string length using gut is 
just a pain to tune. The only reasonable choice is to provide a better tuning 
mechanism such as the planetary gear tuners.<o:p></o:p></a></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>Anyway, thanks 
for your patience as I work through this. It has been fun and now I think I 
understand what is happening.<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p 
class=MsoPlainText>Regards<o:p></o:p></p><p 
class=MsoPlainText>David<o:p></o:p></p><p class=MsoPlainText><o:p>&!
 nbsp;</o:p></p><p class=MsoPlainText>-----Original Message-----<br>From!
 : [email protected] [mailto:[email protected]] On Behalf Of 
David van Ooijen<br>Sent: Friday, December 20, 2013 9:03 AM<br>Cc: Lute 
List<br>Subject: [LUTE] Re: Question on String Tension</p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>&nbsp;&nbsp; 
&gt;&gt; When I plot the partial derivative of F'(T) using the values 
for<o:p></o:p></p><p class=MsoPlainText>&nbsp;&nbsp; this string I find that 
the sensitivity is actually quite small; less<o:p></o:p></p><p 
class=MsoPlainText>&nbsp;&nbsp; than 1/10th of a hertz per 
Newton<o:p></o:p></p><p class=MsoPlainText>&nbsp;&nbsp; 
&lt;&lt;<o:p></o:p></p><p class=MsoPlainText>&nbsp;&nbsp; Don't think in Hertz. 
The difference between 440 and 441Hz is a smaller<o:p></o:p></p><p 
class=MsoPlainText>&nbsp;&nbsp; difference in pitch than between 40 and 41 Hz. 
Think in cents, it makes<o:p></o:p></p><p class=MsoPlainText>&nbsp;&nbsp; 
calculating easier, and the results are easer to understand too.<o:p></o:p></p>!
 <p class=MsoPlainText>&nbsp;&nbsp; David<o:p></o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>&nbsp;&nbsp; 
--<o:p></o:p></p><p class=MsoPlainText><o:p>&nbsp;</o:p></p><p 
class=MsoPlainText><o:p>&nbsp;</o:p></p><p class=MsoPlainText>To get on or off 
this list see list information at <a 
href="http://www.cs.dartmouth.edu/~wbc/lute-admin/index.html";><span 
style='color:windowtext;text-decoration:none'>http://www.cs.dartmouth.edu/~wbc/lute-admin/index.html</span></a><o:p></o:p></p></div></body></html>
------=_NextPart_001_0004_01CF029B.5B4EA1A0--

--

Reply via email to