It was earlier in this thread. I would have thought that the proper code would look more like:
10 a$="your machine code here" 20 a%=varptr(a$): call (peek(a%+1)+256*peek(a%+2)) On Thu, Sep 19, 2019 at 12:33 PM Stephen Adolph <[email protected]> wrote: > yah thats not up to date. where did you get that? > I can post a correction. > > On Thu, Sep 19, 2019 at 1:31 PM Dan Higdon <[email protected]> wrote: > >> I'm still struggling to understand how this works: >> >> 10 a$="Code in ASCII" >> 20 call varptr(a$) >> >> Doesn't varptr(a$) return the address of the string descriptor, which is >> [len,lo,hi]? Wouldn't you have to synthesize the call address from >> lo+hi*256? >> >> Or is there something magical about how constant strings are stored? And >> how do you relocate the code? Or is the first entry in the string table a >> known address, and you just assemble for that position? >> >> Thanks! >> >> On Fri, Sep 13, 2019 at 10:30 AM Kurt McCullum <[email protected]> >> wrote: >> >>> >>> It would appear that Steve already came up with a simple solution to my >>> problem. I just had to find the file "embedding short ML routines in >>> BASIC.txt" >>> >>> 10 a$="Code in ASCII" Zeros not valid but I can work with that. >>> 20 call varptr(a$) >>> >>> Simple solution Steve. My thanks to you for putting that file together. >>> >>> Kurt >>> >>
