At 16:39 +0100 2003.11.19, Rafael Garcia-Suarez wrote: >What does > perl -le 'print $!=22' >on your system ?
22. >Can you reproduce this bug with $! in place of $^E ? I tested, but neglected to mention. No, $! works fine (unless observing $^E already changed the value of $!): $ perl -le '$^E = -1728; print $!+0 for 0,1; print $^E+0 for 0,1' -1728 -1728 -1728 22 $ perl -le '$^E = -1728; print $^E+0 for 0,1; print $!+0 for 0,1' -1728 22 22 22 Changing the initial $^E to $! makes absolutely no difference: $ perl -le '$! = -1728; print $!+0 for 0,1; print $^E+0 for 0,1' -1728 -1728 -1728 22 $ perl -le '$! = -1728; print $^E+0 for 0,1; print $!+0 for 0,1' -1728 22 22 22 -- Chris Nandor [EMAIL PROTECTED] http://pudge.net/ Open Source Development Network [EMAIL PROTECTED] http://osdn.com/
