At 10:59 -0500 2003.11.19, Dan Sugalski wrote: >On Wed, 19 Nov 2003, Chris Nandor wrote: > >> $ perl -le '$^E = -1728; print $^E+0 for 0,1; print $!+0 for 0,1' >> -1728 >> 22 >> 22 >> 22 > >Given that on Unix systems $^E and $! are identical, and that $! is >directly tied to errno, this certainly isn't surprising. Anything that >afects errno (like, say, IO) may then affect $! and $^E identically.(And >$!/$^E non-indentically on systems where they're separate) > >Basically you're using a variable that can be affected by external things >in a way that pretty much guarantees that external things will be >happening. That it changes isn't much of a surprise. ($!/$^E may get >modified by some signal handlers too, depending on what you do, so there's >not even any guarantee that "$^E = 42; $^E++;" will end up with $^E set to >43.
It should not change its value merely by accessing its value. It's never done that in previous versions of perl, and shouldn't do it now. If you're saying that the value of $! changing after $^E changes is not surprising, yes, I agree. But the value of $^E changing is very surprising, and wrong. -- Chris Nandor [EMAIL PROTECTED] http://pudge.net/ Open Source Development Network [EMAIL PROTECTED] http://osdn.com/
