I'd say something like: a = NSNumber.numberWithDouble(0.0/0.0) which returns the exact same thing as: a = (0.0/0.0)
Why do you need that? :P -- Thibault Martin-Lagardette On Jan 7, 2011, at 15:52, Joel Reymont wrote: > How do you do this? > > [NSNumber numberWithDouble:NAN] > > NAN is defined as __builtin_nanf("0x7fc00000") in math.h > > Thanks, Joel > > --- > http://wagerlabs.com | @wagerlabs | http://www.linkedin.com/in/joelreymont > > > > > > _______________________________________________ > MacRuby-devel mailing list > MacRuby-devel@lists.macosforge.org > http://lists.macosforge.org/mailman/listinfo.cgi/macruby-devel _______________________________________________ MacRuby-devel mailing list MacRuby-devel@lists.macosforge.org http://lists.macosforge.org/mailman/listinfo.cgi/macruby-devel