Yep.

Laurent

On Jan 7, 2011, at 9:41 AM, Joel Reymont wrote:

> 
> On Jan 7, 2011, at 5:21 PM, Thibault Martin-Lagardette wrote:
> 
>> I'd say something like:
>>      a = NSNumber.numberWithDouble(0.0/0.0)
>> which returns the exact same thing as:
>>      a = (0.0/0.0)
> 
> Does the resulting NaN automatically convert to NSNumber?
> 
> I need to pass the object initialized this way to a function in another 
> framework, e.g.
> 
>    [focusParameter setNumberValue:[NSNumber numberWithDouble:NAN]];
> 
> ---
> http://wagerlabs.com | @wagerlabs | http://www.linkedin.com/in/joelreymont
> 
> 
> 
> 
> 
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