Hi there, My son the computer engineer helped me yesterday. He had to clear out all of my preferences because they had become corrupted.
Make sure you have Mail also set up to receive POP mail. I originally had Gmail set up as an IMAP acount and it gave me nothing but problems. Bottom line; it sounds like your problem may be with Mail and not with GMail. Good luck. On Nov 15, 2010, at 5:12 PM, Christina wrote: > I don't know what I am doing wrong but I am trying to add a gmail account to > apple mail and it just won't work. I have followed all the steps to the best > of my ability and I just cannot get it to work. The closest I've come is > getting an error message saying that pop.gmail.com cannot be verified and may > be a security risk if I continue. Those are not the exact words but it's the > general idea. Are there any ideas as to what is going on. I've read > everything I could on the gmail website to see why I've gotten this error > message and also as to why this is not working at all. I currently have a > pop gmail account working in apple mail and I've tried using similar settings > for the new gmail address but I cannot get it to work. On the gmail side I > did enable pop mail so that isn't the problem. Someone else set up the first > gmail account for me but I just cannot seem to figure out how to set up the > second account on my own. > > Thanks for any hints, > Christina > > -- > You received this message because you are subscribed to the Google Groups > "MacVisionaries" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/macvisionaries?hl=en. > -- You received this message because you are subscribed to the Google Groups "MacVisionaries" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/macvisionaries?hl=en.
