Just iterate over non-zero values of y for the second term. On Wed, Jan 27, 2010 at 12:06 PM, Jake Mannix <jake.man...@gmail.com> wrote:
> x^2 + y.(y-x) > > Hmm... how exactly do you do both a dot product and a subtraction on one > iteration? I guess if x is dense, > -- Ted Dunning, CTO DeepDyve
