Karl O. Pinc wrote:
>
>On 02/10/2009 02:07:23 PM, Karl O. Pinc wrote:
>>
>> On 02/10/2009 10:20:51 AM, Brian Canty wrote:
>>> I was wondering if anyone knows of any command you can use to find
>>> out
>>> who is subscribed to all mailman lists.
>
>Somehow the "cut" command got mangled. Should be:
>
> list_lists \
> | tail -n +2 \
> | awk '{print $1;}' \
> | xargs -n 1 bash -c 'list_members $0 | xargs -n 1 echo $0:' \
> | grep [email protected] \
> | cut -d : -f 1
>
>> Gets you all the lists that [email protected] is subscribed to.
So does
bin/find_member [email protected]
and much more simply.
--
Mark Sapiro <[email protected]> The highway is for gamblers,
San Francisco Bay Area, California better use your sense - B. Dylan
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