Karl O. Pinc wrote:
>
>On 02/10/2009 10:20:51 AM, Brian Canty wrote:
>> I was wondering if anyone knows of any command you can use to find out
>> who is subscribed to all mailman lists.
>
>list_lists | tail -n +2 | awk '{print $1;}' | xargs -n 1 list_members |
>sort -u
>
>Gets you all the members of all the lists.


So does

bin/find_member .

or

bin/find_member @

-- 
Mark Sapiro <[email protected]>        The highway is for gamblers,
San Francisco Bay Area, California    better use your sense - B. Dylan

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