Given the additional factor of a few cups of coffee before riding to work (which would cause the rider to ride faster in a straight line), and a few pints before riding home (which would cause the rider to weave all over the place), I believe the distance measure should reflect
(a + b)/sqr(a^2+b^2) x a^3 + b/c - d + 2 x 0 :) -----Original Message----- From: Christof Kaiser [mailto:[EMAIL PROTECTED] Sent: Friday, April 02, 2004 9:43 AM To: 'MapInfo-L' Subject: MI-L Re: weekend question: ratio between like the crow flies and road distance Bill worte: > is (a + b) / sqr(a^2+b^2). If a and b are equal, then this reduces to 2a / > sqr(2*a^2) or 2 / sqr(2), or about 1.414. > > That's pretty close to what you get, so you must be riding about as far in > the east-west direction as you do in the north-south direction? Not if the street grid is twisted against the meridians? Anyway, the case is a bit different as the roads are far from being a grid. Over here, you often have curved, windy roads which go back to a persistent medieval town structure. Another obstacle are footpaths in parks I use on the way. Park paths are neither straight not have short connections. In fact, I think it is a competition to put as much length (of paths) in a parks as possible to make it look bigger for the visitor. OK, I ll give it a go and do another estimation on my way home which will start now. cheers christof --------------------------------------------------------------------- List hosting provided by Directions Magazine | www.directionsmag.com | To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] Message number: 11255 --------------------------------------------------------------------- List hosting provided by Directions Magazine | www.directionsmag.com | To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] Message number: 11256
