A snippet of code does not help in general. Please take your time to create a simple, standalone code that reproduces your problem and post that code in this mailing list so that we can easily test.
Here is the code, based on yours, that works for me. im = Image.open("icon.jpg") ax = gca() limx = ax.get_xlim() limy = ax.get_ylim() ax.set_autoscale_on(False) [x0, y0], [x1, y1] = ax.bbox.get_points() datawidth = limx[1] - limx[0] dataheight = limy[1] - limy[0] pixelwidth = x1 - x0 pixelheight = y1 - y0 adaptedwidth = im.size[0] * (datawidth/pixelwidth) adaptedheight = im.size[1] * (dataheight/pixelheight) ax.imshow(im, origin="lower", extent=(0.5, 0.5+adaptedwidth, 0.5, 0.5+adaptedheight)) plt.draw() -JJ On Fri, Jul 31, 2009 at 3:44 PM, Bas van Leeuwen<leeu...@gmail.com> wrote: > Hello, > > I tried to implement a solution for this issue. Basically I want to > give the x and y position in datacoords and the width + height in > pixels. > However, when using the following code: > > im = Image.open("../Icons/Program Icon.png") > > limx = self.mainAxes.get_xlim() > limy = self.mainAxes.get_ylim() > > [x0, y0], [x1, y1] = self.mainAxes.bbox.get_points() > > datawidth = limx[1] - limx[0] > dataheight = limy[1] - limy[0] > pixelwidth = x1 - x0 > pixelheight = y1 - y0 > adaptedwidth = im.size[0] * (datawidth/pixelwidth) > adaptedheight = im.size[1] * (dataheight/pixelheight) > > > for peak in Blocks.peaks(self.quote.Close, > self.peakSpanSlider.value()): > self.mainAxes.imshow(im, origin = 'lower', extent = > (date2num(peak.datetime), date2num(peak.datetime) + 100 , 400, 425)) # > left right bottom top > self.mainAxes.set_xlim(limx) > self.mainAxes.set_ylim(limy) > > There is no visible result. When zooming in to a place where an image > should be present I encounter the following error every time I move > the mouse. > > Traceback (most recent call last): > File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4.py", > line 135, in mouseReleaseEvent > FigureCanvasBase.button_release_event( self, x, y, button ) > File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py", > line 1198, in button_release_event > self.callbacks.process(s, event) > File "C:\Python25\lib\site-packages\matplotlib\cbook.py", line 155, in > process > func(*args, **kwargs) > File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py", > line 2048, in release_zoom > self.draw() > File "C:\Python25\lib\site-packages\matplotlib\backend_bases.py", > line 2070, in draw > self.canvas.draw() > File "C:\Python25\lib\site-packages\matplotlib\backends\backend_qt4agg.py", > line 133, in draw > FigureCanvasAgg.draw(self) > File "C:\Python25\lib\site-packages\matplotlib\backends\backend_agg.py", > line 279, in draw > self.figure.draw(self.renderer) > File "C:\Python25\lib\site-packages\matplotlib\figure.py", line 772, in draw > for a in self.axes: a.draw(renderer) > File "C:\Python25\lib\site-packages\matplotlib\axes.py", line 1545, in draw > im.draw(renderer) > File "C:\Python25\lib\site-packages\matplotlib\image.py", line 233, in draw > im = self.make_image(renderer.get_image_magnification()) > File "C:\Python25\lib\site-packages\matplotlib\image.py", line 220, > in make_image > rx = widthDisplay / numcols > ZeroDivisionError: float division > > Any idea what might cause this issue? Did I do something wrong? I know > it's not pretty, but it should work right? > > Cheers! > Bas > > > > 2009/7/30 Bas van Leeuwen <leeu...@gmail.com>: >> Hi JJ, >> >> Thank you for your kind and speedy reply, I completely glanced over >> the extent parameter. >> Datacoords are actually what I need so this is perfect for me. >> >> To clarify what I want, I want to mark certain parts of a graph with >> an icon representing the reason it's interesting. Icons are for peaks, >> trends, correlation, etc. >> >> Thank you very much! >> >> Bas >> >> >> 2009/7/30 Jae-Joon Lee <lee.j.j...@gmail.com>: >>> The location of the image can be set by specifying the "extent" >>> keyword, however, this is set in data coordinate. >>> figimage may be close to what you want. >>> >>> http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.figimage >>> >>> As far as I know, there is no direct support in matplotlib to place an >>> image with arbitrary transformation. But it may not be difficult to >>> implement. However, "annotate a plot with icons" is not enough to >>> figure out what you really want. >>> Maybe some screenshots from other plotting tool will be helpful. Or, >>> please elaborate how you want to position your image. >>> >>> -JJ >>> >>> >>> On Thu, Jul 30, 2009 at 12:11 PM, Bas van Leeuwen<leeu...@gmail.com> wrote: >>>> Hi all, >>>> >>>> Is there any way to annotate a plot with icons? >>>> The only way to include an image that I've found is using imshow, but >>>> imshow does not accept (x,y) coordinates. >>>> >>>> There probably is an easy solution, but I have not been able to find >>>> any. Please be patient :-) >>>> >>>> Thank you in advance for your reply, >>>> Bas van Leeuwen >>>> >>>> PS, I'm sorry if this mail arrives multiple times, I didn't see the >>>> previous one in the archive. >>>> >>>> ------------------------------------------------------------------------------ >>>> Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day >>>> trial. Simplify your report design, integration and deployment - and focus >>>> on >>>> what you do best, core application coding. Discover what's new with >>>> Crystal Reports now. http://p.sf.net/sfu/bobj-july >>>> _______________________________________________ >>>> Matplotlib-users mailing list >>>> Matplotlib-users@lists.sourceforge.net >>>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >>>> >>> >> > > ------------------------------------------------------------------------------ > Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day > trial. Simplify your report design, integration and deployment - and focus on > what you do best, core application coding. Discover what's new with > Crystal Reports now. http://p.sf.net/sfu/bobj-july > _______________________________________________ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > ------------------------------------------------------------------------------ Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day trial. Simplify your report design, integration and deployment - and focus on what you do best, core application coding. Discover what's new with Crystal Reports now. http://p.sf.net/sfu/bobj-july _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users