Dear Neeraj, more complex way is
PTDF = inv(J)*Jf where J is Jacobian (dimension nb-1xnb-1) what is Jf? is it similar Bf (dimension ntxnb-1)? Is there any paper I can cite? 16 февраля 2012 г. 15:20 пользователь <[email protected]> написал: > Dear Tatiyan, > > Simplistic way to find the PTDF matrix is given below: > > PTDF = inv(B)* Bf > > Where > > B = reduced nodal susceptance matrix > Bf = reduced matrix with the branch susceptances > > This formula is also used in MATPOWER. > > > best regards > > Neeraj Gupta > Research Scholar > Indian Institute of Technology Kanpur > India > > Tatiana Vaskovskaya > > I can't find info about PDTF. Can anybody give a formula for computing > > PTDFs and/or a source where I can find it? > > > > >
