You haven’t said which are buses i and j in your example, but I was not able to reproduce result with the case you say you are running …
define_constants; mpc = loadcase(‘case9'); mpc.branch(:, BR_B) = 0; mpc.branch(:, TAP) = 0; mpc.branch(:, RATE_A) = 0; r = runopf(mpc); However, in a situation like this, I suggest you use the branch parameters and the solved voltages to compute each of the values in Figure 3-1 in the User’s Manual to fully understand what is flowing where and why. -- Ray Zimmerman Senior Research Associate B30 Warren Hall, Cornell University, Ithaca, NY 14853 phone: (607) 255-9645 On Nov 10, 2013, at 6:52 PM, Spyridon Gian <[email protected]> wrote: > Dr Zimmerman, > > I am attaching a pdf that shows a situation where the MatPower gives same - > sign reactive flows. > For example, consider bus i and bus j. From bus i , 16MVAr leave , and from > bus j , 11MVAr leave. So they meat somewhere in the middle and the total > losses are 27 MVAr. Why is this happening ? > > The situation is for the 'case9.m' (runopf) with the following changes: no > line limits (RATE_A=0), line capacitance (b=0) and no tap changers. > > Thank you > <Same sign.pdf>
