Could you please specify a personal email so that I can send you the matpower file as it is, ready to run ? Thank you
From: [email protected] Subject: Re: Same sign flows Date: Mon, 11 Nov 2013 10:00:26 -0500 To: [email protected] You haven’t said which are buses i and j in your example, but I was not able to reproduce result with the case you say you are running … define_constants;mpc = loadcase(‘case9');mpc.branch(:, BR_B) = 0;mpc.branch(:, TAP) = 0;mpc.branch(:, RATE_A) = 0;r = runopf(mpc); However, in a situation like this, I suggest you use the branch parameters and the solved voltages to compute each of the values in Figure 3-1 in the User’s Manual to fully understand what is flowing where and why. -- Ray ZimmermanSenior Research AssociateB30 Warren Hall, Cornell University, Ithaca, NY 14853phone: (607) 255-9645 On Nov 10, 2013, at 6:52 PM, Spyridon Gian <[email protected]> wrote:Dr Zimmerman, I am attaching a pdf that shows a situation where the MatPower gives same - sign reactive flows.For example, consider bus i and bus j. From bus i , 16MVAr leave , and from bus j , 11MVAr leave. So they meat somewhere in the middle and the total losses are 27 MVAr. Why is this happening ? The situation is for the 'case9.m' (runopf) with the following changes: no line limits (RATE_A=0), line capacitance (b=0) and no tap changers. Thank you<Same sign.pdf>
