Hi Nur,
Dont divide R and X with the voltage. I get the following power flow
without those two lines.
------------
runpf('LV10')
MATPOWER Version 6.0b1, 01-Jun-2016 -- AC Power Flow (Newton)
Newton's method power flow converged in 5 iterations.
Converged in 0.02 seconds
================================================================================
| System Summary
|
================================================================================
How many? How much? P (MW) Q (MVAr)
--------------------- ------------------- -------------
-----------------
Buses 12 Total Gen Capacity 261.0 -302.0 to 302.0
Generators 11 On-line Capacity 250.0 -300.0 to 300.0
Committed Gens 1 Generation (actual) 1.2 0.5
Loads 10 Load 1.0 0.3
Fixed 10 Fixed 1.0 0.3
Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
Shunts 0 Shunt (inj) -0.0 0.0
Branches 11 Losses (I^2 * Z) 0.23 0.16
Transformers 0 Branch Charging (inj) - 0.0
Inter-ties 0 Total Inter-tie Flow 0.0 0.0
Areas 1
Minimum Maximum
------------------------- --------------------------------
Voltage Magnitude 0.717 p.u. @ bus 11 1.000 p.u. @ bus 1
Voltage Angle -5.40 deg @ bus 11 0.00 deg @ bus 1
P Losses (I^2*R) - 0.06 MW @ line 1-2
Q Losses (I^2*X) - 0.04 MVAr @ line 1-2
================================================================================
| Bus Data
|
================================================================================
Bus Voltage Generation Load
# Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)
----- ------- -------- -------- -------- -------- --------
1 1.000 0.000* 1.23 0.46 - -
2 0.950 -0.744 - - 0.10 0.03
3 0.905 -1.483 - - 0.10 0.03
4 0.864 -2.206 - - 0.10 0.03
5 0.828 -2.898 - - 0.10 0.03
6 0.797 -3.541 - - 0.10 0.03
7 0.770 -4.116 - - 0.10 0.03
8 0.749 -4.607 - - 0.10 0.03
9 0.733 -4.993 - - 0.10 0.03
10 0.722 -5.260 - - 0.10 0.03
11 0.717 -5.397 - - 0.10 0.03
12 1.000 0.000 - - - -
-------- -------- -------- --------
Total: 1.23 0.46 1.00 0.30
================================================================================
| Branch Data
|
================================================================================
Brnch From To From Bus Injection To Bus Injection Loss (I^2 *
Z)
# Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q
(MVAr)
----- ----- ----- -------- -------- -------- -------- --------
--------
1 1 2 1.23 0.46 -1.17 -0.42 0.055
0.04
2 2 3 1.07 0.39 -1.03 -0.36 0.046
0.03
3 3 4 0.93 0.33 -0.89 -0.30 0.038
0.03
4 4 5 0.79 0.27 -0.76 -0.25 0.030
0.02
5 5 6 0.66 0.22 -0.64 -0.20 0.023
0.02
6 6 7 0.54 0.17 -0.52 -0.16 0.016
0.01
7 7 8 0.42 0.13 -0.41 -0.13 0.011
0.01
8 8 9 0.31 0.10 -0.30 -0.09 0.006
0.00
9 9 10 0.20 0.06 -0.20 -0.06 0.003
0.00
10 10 11 0.10 0.03 -0.10 -0.03 0.001
0.00
11 1 12 0.00 0.00 0.00 0.00 0.000
0.00
--------
--------
Total: 0.228
0.16
On Tue, Oct 25, 2016 at 10:31 PM, Nazurah Nasir <[email protected]>
wrote:
>
>
> Hi all MatPower community,
>
> I am trying to develop a simple LV network in radial network distribution.
> However, my model did not converge or if I scale the R and X, the results
> is too big (which means the R,X) scaling is wrong. I tried for one month
> now but still could get around why it is not converging.
>
> I need to work on this PowerFlow to work inside my bilevel programming
> loop. but it seems my code won't work because the power flow is not
> converging.
>
> I need help on verifying my parameter. Attached is my code that I build.
> As the MatPower is in three phase balanced, I lumped my loads that
> connected to a bus as one load, hence the voltage at the bus is 0.415kV. My
> input power are all in kW, hence I change the impedance values accordingly
> by multiplying it by 1000. The input power is just a dummy value of 0.1MW
> because it will update itself in a loop. But since input power is in kW, I
> should divide that by 1000 right?
>
> Thank you so much for the help.
>
>
> Best regards,
> Nur
>
>
