If you want to do things properly, I guess you would have to do *all* of
the following:
- First, MATPOWER expects baseMVA to be in MW. If you want to use a
p.u. system based around Volts and 1 kW (instead of the traditional kV and
100 MW), then you need baseMVA=0.001 at the beginning of your case file.
- Expressing voltages in pu should be no problem, just divide the
quantity in volts by your voltage levels (in your case I see it's only one,
415 Volts)
- Now, MATPOWER expects all power quantities (P, Q) to be expressed in
MW. So if your values are in kW, divide them by 1000.
- Finally, to convert resistances and reactances (R, X), use your
baseMVA and voltage base as follows: take the initial quantity in Ohms, and
multiply it by: baseMVA / Vbase^2 = 1000 Watts / (415 Volts)^2 =
5.806357961968356e-03
- You don't have Bshunt values in your case, but if you had, the
conversion factor would be just the inverse of the one used for resistance
and reactance.
I hope I'm not missing anything, I think that's all you need in your case.
--
Jose L. Marin
Grupo AIA
2016-10-26 14:44 GMT+02:00 Nazurah Nasir <nurnazu...@gmail.com>:
> But does that means I should not divide my input power data by 1000 to
> make it in MW? If I do that, it won't converge. For example, these are my
> Power input for one time:
>
> Columns 1 through 6
> 1.0000 3.0000 0 0 0 0
> 2.0000 1.0000 0.0012 0.0004 0 0
> 3.0000 1.0000 0.0019 0.0006 0 0
> 4.0000 1.0000 0.0006 0.0002 0 0
> 5.0000 1.0000 0.0024 0.0008 0 0
> 6.0000 1.0000 0.0012 0.0004 0 0
> 7.0000 1.0000 0.0010 0.0003 0 0
> 8.0000 1.0000 0.0023 0.0008 0 0
> 9.0000 1.0000 0.0005 0.0002 0 0
> 10.0000 1.0000 0.0006 0.0002 0 0
> 11.0000 1.0000 0.0012 0.0004 0 0
> 12.0000 1.0000 0 0 0 0
> Columns 7 through 12
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> 1.0000 1.0000 0 0.4150 1.0000 1.1000
> Column 13
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
> 0.9400
>
> Thank you very much for the help
>
> Yours sincerely,
> Nur
>
> On Wed, Oct 26, 2016 at 11:14 PM, Nazurah Nasir <nurnazu...@gmail.com>
> wrote:
>
>> Aren't I supposed to make the R and X in p.u. if I want to use them in
>> MATPOWER? Regardless, your simulation seems to be more sensible. But, I
>> just curious, so we don't necessarily change the R and X into p.u. values?
>>
>> Thanks for the response.
>>
>> On Wed, Oct 26, 2016 at 3:26 PM, Saranya A <asar...@gmail.com> wrote:
>>
>>> Hi Nur,
>>> Dont divide R and X with the voltage. I get the following power flow
>>> without those two lines.
>>>
>>> ------------
>>> runpf('LV10')
>>>
>>> MATPOWER Version 6.0b1, 01-Jun-2016 -- AC Power Flow (Newton)
>>>
>>> Newton's method power flow converged in 5 iterations.
>>>
>>> Converged in 0.02 seconds
>>> ============================================================
>>> ====================
>>> | System Summary
>>> |
>>> ============================================================
>>> ====================
>>>
>>> How many? How much? P (MW) Q
>>> (MVAr)
>>> --------------------- ------------------- -------------
>>> -----------------
>>> Buses 12 Total Gen Capacity 261.0 -302.0 to
>>> 302.0
>>> Generators 11 On-line Capacity 250.0 -300.0 to
>>> 300.0
>>> Committed Gens 1 Generation (actual) 1.2 0.5
>>> Loads 10 Load 1.0 0.3
>>> Fixed 10 Fixed 1.0 0.3
>>> Dispatchable 0 Dispatchable -0.0 of -0.0 -0.0
>>> Shunts 0 Shunt (inj) -0.0 0.0
>>> Branches 11 Losses (I^2 * Z) 0.23 0.16
>>> Transformers 0 Branch Charging (inj) - 0.0
>>> Inter-ties 0 Total Inter-tie Flow 0.0 0.0
>>> Areas 1
>>>
>>> Minimum Maximum
>>> ------------------------- -----------------------------
>>> ---
>>> Voltage Magnitude 0.717 p.u. @ bus 11 1.000 p.u. @ bus 1
>>> Voltage Angle -5.40 deg @ bus 11 0.00 deg @ bus 1
>>> P Losses (I^2*R) - 0.06 MW @ line 1-2
>>> Q Losses (I^2*X) - 0.04 MVAr @ line 1-2
>>>
>>> ============================================================
>>> ====================
>>> | Bus Data
>>> |
>>> ============================================================
>>> ====================
>>> Bus Voltage Generation Load
>>> # Mag(pu) Ang(deg) P (MW) Q (MVAr) P (MW) Q (MVAr)
>>> ----- ------- -------- -------- -------- -------- --------
>>> 1 1.000 0.000* 1.23 0.46 - -
>>> 2 0.950 -0.744 - - 0.10 0.03
>>> 3 0.905 -1.483 - - 0.10 0.03
>>> 4 0.864 -2.206 - - 0.10 0.03
>>> 5 0.828 -2.898 - - 0.10 0.03
>>> 6 0.797 -3.541 - - 0.10 0.03
>>> 7 0.770 -4.116 - - 0.10 0.03
>>> 8 0.749 -4.607 - - 0.10 0.03
>>> 9 0.733 -4.993 - - 0.10 0.03
>>> 10 0.722 -5.260 - - 0.10 0.03
>>> 11 0.717 -5.397 - - 0.10 0.03
>>> 12 1.000 0.000 - - - -
>>> -------- -------- -------- --------
>>> Total: 1.23 0.46 1.00 0.30
>>>
>>> ============================================================
>>> ====================
>>> | Branch Data
>>> |
>>> ============================================================
>>> ====================
>>> Brnch From To From Bus Injection To Bus Injection Loss (I^2
>>> * Z)
>>> # Bus Bus P (MW) Q (MVAr) P (MW) Q (MVAr) P (MW) Q
>>> (MVAr)
>>> ----- ----- ----- -------- -------- -------- -------- --------
>>> --------
>>> 1 1 2 1.23 0.46 -1.17 -0.42 0.055
>>> 0.04
>>> 2 2 3 1.07 0.39 -1.03 -0.36 0.046
>>> 0.03
>>> 3 3 4 0.93 0.33 -0.89 -0.30 0.038
>>> 0.03
>>> 4 4 5 0.79 0.27 -0.76 -0.25 0.030
>>> 0.02
>>> 5 5 6 0.66 0.22 -0.64 -0.20 0.023
>>> 0.02
>>> 6 6 7 0.54 0.17 -0.52 -0.16 0.016
>>> 0.01
>>> 7 7 8 0.42 0.13 -0.41 -0.13 0.011
>>> 0.01
>>> 8 8 9 0.31 0.10 -0.30 -0.09 0.006
>>> 0.00
>>> 9 9 10 0.20 0.06 -0.20 -0.06 0.003
>>> 0.00
>>> 10 10 11 0.10 0.03 -0.10 -0.03 0.001
>>> 0.00
>>> 11 1 12 0.00 0.00 0.00 0.00 0.000
>>> 0.00
>>> --------
>>> --------
>>> Total: 0.228
>>> 0.16
>>>
>>> On Tue, Oct 25, 2016 at 10:31 PM, Nazurah Nasir <nurnazu...@gmail.com>
>>> wrote:
>>>
>>>>
>>>>
>>>> Hi all MatPower community,
>>>>
>>>> I am trying to develop a simple LV network in radial network
>>>> distribution. However, my model did not converge or if I scale the R and X,
>>>> the results is too big (which means the R,X) scaling is wrong. I tried for
>>>> one month now but still could get around why it is not converging.
>>>>
>>>> I need to work on this PowerFlow to work inside my bilevel programming
>>>> loop. but it seems my code won't work because the power flow is not
>>>> converging.
>>>>
>>>> I need help on verifying my parameter. Attached is my code that I
>>>> build. As the MatPower is in three phase balanced, I lumped my loads that
>>>> connected to a bus as one load, hence the voltage at the bus is 0.415kV. My
>>>> input power are all in kW, hence I change the impedance values accordingly
>>>> by multiplying it by 1000. The input power is just a dummy value of 0.1MW
>>>> because it will update itself in a loop. But since input power is in kW, I
>>>> should divide that by 1000 right?
>>>>
>>>> Thank you so much for the help.
>>>>
>>>>
>>>> Best regards,
>>>> Nur
>>>>
>>>>
>>>
>>
>
