thank you, i did it and it works
++++++++++++++++++++++++++++++++++++++++++++
clear all;
clc;
define_constants;
factor = [0.827315297246503; 0.870524914020136; 0.89225313150181;
0.874238893371013; 0.841447907563717; 0.84108393381471; 0.79110106954204;
0.797588753768103; 0.801421029392904; 0.822018440318329; 0.864051234184459;
0.876248439711015; 0.888800014120353; 0.922571691519356; 0.978924730305068;
1; 0.975195764982014; 0.903702013699042; 0.8424313185939; 0.786194728460529;
0.846555864529582; 0.851944597303249; 0.834213349185084; 0.84694392020701;];
mpc0 = loadcase('OETC_OPF');
nt = length(factor);
for t = 1:nt
mpc(t) = mpc0;
[mpc(t).bus] = ...
scale_load(factor(t), mpc(t).bus);
results(t) = runopf(mpc(t));
end
++++++++++++++++++++++++++++++++++++++++++++
put how i can do the same job but using the function
most_summary()
can you write the code, because i tried a lot but it did not work using the
function most_summary()
On 19 April 2018 at 23:56, Ray Zimmerman <[email protected]> wrote:
> Use the scale_load()
> <http://www.pserc.cornell.edu/matpower/docs/ref/matpower6.0/scale_load.html>
> function
> in a loop, something like shown here: https://www.mail-
> archive.com/[email protected]/msg06477.html
>
> Ray
>
>
> On Apr 17, 2018, at 12:27 PM, Mohammed Alhajri <[email protected]> wrote:
>
> Hello all,
>
> i want to run dc opf for 24 hr
>
> i have the load scale for 24hr, and i want to multiply each load bus with
> this load scale to get the load for 24hr in MW
>
> how can i do that?
>
> i have attached:
>
> - case file
> -load scale
> -dcopf code
>
>
>
> <load scale.xlsx><OETC_DCOPF_2.m><OETC_OPF.m>
>
>
>