The OPF tests include such an example.

See, for example, the code starting at line 228 in t_opf_default.m 
<https://github.com/MATPOWER/matpower/blob/a6a489c3d3a83f5c65fc7e0a5dc5306eb7cc6ac0/lib/t/t_opf_default.m#L228>.

    Ray


> On Apr 25, 2019, at 11:45 AM, Jubeyer Rahman <[email protected]> wrote:
> 
> Hi,
> 
> Just a query, can you point me any example code that demonstrates the whole 
> direct specification of extended OPF formulation described in section 7.1?
> 
> Regards,
> Jubeyer
> 
> 
> 
> On Thu, Apr 25, 2019 at 10:50 AM Ray Zimmerman <[email protected] 
> <mailto:[email protected]>> wrote:
> The A matrix of (6.38) in the MATPOWER 7.0b1 User’s Manual will have to 
> include the coefficients for all variables, both Pg and z.
> 
>    Ray
> 
>> On Apr 22, 2019, at 10:06 PM, Jubeyer Rahman <[email protected] 
>> <mailto:[email protected]>> wrote:
>> 
>> 
>> Hi,
>> 
>> Thanks a lot for your reply. 
>> 
>> Are you referring to Ar matrix ( The A matrix multiplied with Pg here) from 
>> the reserve formulation (since this is a subtraction with the variable z)?
>> 
>> So, If I want to implement anything like, Pg-z*factor= Po; where Po is the 
>> dispatch in pre-contingency case how should I do it?
>> 
>> The way I am thinking to do is, I will run the pre-contingency case, 
>> preserve the 'Pg' data, and pass it as the 'Pmin' for the redistpatch 
>> period. Then I will add the z variable with the OPF structure.
>> 
>>  I apologize I could not come up with a proper formulation as I am not quite 
>> sure what I am thinking is correct or not.
>> 
>> Regards,
>> Jubeyer
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> 
>> On Tue, Apr 16, 2019 at 9:01 AM Ray Zimmerman <[email protected] 
>> <mailto:[email protected]>> wrote:
>> Add a single constraint of the form …
>> 
>> A * Pg - z  = 0
>> 
>> … where A is a row vector, Pg is the vector of generation and z is a new 
>> scalar variable representing the total amount of the resdispatch.
>> 
>>    Ray
>> 
>> 
>>> On Apr 9, 2019, at 5:56 PM, Jubeyer Rahman <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> 
>>> And for redispatch case as you have mentioned , if I want the generators 
>>> redispatch in a certain way (make them produce power like Pg+some 
>>> factor*some variable), how should I do that?
>>> 
>>> On Tue, Apr 9, 2019 at 4:56 PM Jubeyer Rahman <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> I am really sorry that I haven't been able to make it more clear. However, 
>>> I will come up with a clear formulation later on.
>>> 
>>> Actually, I have already formualted that and am getting some value for R. 
>>> But I am not quite sure whether I have been able to get the cost 
>>> formulation correct.
>>> 
>>> So, for now , can you only tell me, that if I do get some value for R, 
>>> which is supposed to come from some certain generator's, how can I make 
>>> that calculated as a total power generation Pg+R from the gencost 
>>> information and not from the reserve cost. 
>>> 
>>> On Tue, Apr 9, 2019 at 4:50 PM Ray Zimmerman <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> I’m afraid I still don’t understand the problem you intend to solve. The 
>>> formulation you provided is completely equivalent to the standard OPF with 
>>> some additional variables and constraints that have no effect ultimately 
>>> (since r_i = 0 is feasible).
>>> 
>>> It sounds like you want to apply some kind of constraint to Pg to restrict 
>>> redispatches from some initial dispatch or something, but the formulation 
>>> you provided does not accomplish that.
>>> 
>>> So, it seems like the first step would be to get the problem formulation 
>>> clear and correct, then we can help if you have questions about the 
>>> implementation.
>>> 
>>>     Ray
>>> 
>>> 
>>>> On Apr 9, 2019, at 4:33 PM, Jubeyer Rahman <[email protected] 
>>>> <mailto:[email protected]>> wrote:
>>>> 
>>>> Yes, I don't want the objective function to be affected in that way. The 
>>>> reason of formulating that way is if I don't have all the generators 
>>>> active in my system (in case  I loose one generator for example, I want 
>>>> the rest of the generator's to respond in a certain way).
>>>> 
>>>> On Tue, Apr 9, 2019 at 4:30 PM Ray Zimmerman <[email protected] 
>>>> <mailto:[email protected]>> wrote:
>>>> I think there must be something missing. Because the addition of these 
>>>> variables and constraints will not affect the OPF solution at all. It will 
>>>> be the same as the standard OPF formulation with no reserves. That is, the 
>>>> original solution will still be both optimal (since there is no change to 
>>>> the objective function in (6.34)) and feasible (since r_i = 0 is feasible 
>>>> and imposes no additional restrictions on the problem).
>>>> 
>>>> Your formulation as stated includes no reason for r_i to be non-zero.
>>>> 
>>>>    Ray
>>>> 
>>>> 
>>>> 
>>>>> On Apr 9, 2019, at 3:33 PM, Jubeyer Rahman <[email protected] 
>>>>> <mailto:[email protected]>> wrote:
>>>>> 
>>>>> Ok. Here they go:
>>>>> 
>>>>> similar to 7.2
>>>>> 
>>>>> 0<=r_i<=Pmax
>>>>> 
>>>>> for 7.3: Since I don't want the cost to be calculated separately, I don't 
>>>>> need anything here (reserves from generators should be calculated as the 
>>>>> total power generation cost, no separate cost for generator)
>>>>> 
>>>>> for 7.4
>>>>> pg^i+x*r_i<=pg^i,max
>>>>> 
>>>>> x is given as parameters here.
>>>>> 
>>>>> for 7.5; since I don't have zonal requirement I don't have anything for 
>>>>> that.
>>>>> 
>>>>> Let me know if you need anything for more clarification.
>>>>> 
>>>>> 
>>>>> 
>>>>> On Tue, Apr 9, 2019 at 3:13 PM Ray Zimmerman <[email protected] 
>>>>> <mailto:[email protected]>> wrote:
>>>>> Ok, so you are attempting to modify the existing fixed reserves 
>>>>> implementation to something with a similar, but not identical structure. 
>>>>> I think I need to fully understand the formulation. Can you provide the 
>>>>> equivalent of equations (7.2)–(7.5) for your problem so I can see exactly 
>>>>> where the differences are?
>>>>> 
>>>>>    Ray
>>>>> 
>>>>> 
>>>>>> On Apr 9, 2019, at 11:43 AM, Jubeyer Rahman <[email protected] 
>>>>>> <mailto:[email protected]>> wrote:
>>>>>> 
>>>>>> Ok. Thanks a lot for your reply.
>>>>>> 
>>>>>>  What I am trying to implement is something like this 'Pg+x*R', where 
>>>>>> 'Pg' is real power generation, x is a collection of factors (parameters) 
>>>>>> usually fraction number ranging between 0 and 1, and R will be a 
>>>>>> variable for reserves. Usually the minimum value for R is 0 and maximum 
>>>>>> value is equal to the 'Pmax' for each generator asked to provide 
>>>>>> reserves. What I also want is that the reserve cost to be ignored 
>>>>>> ,rather the cost of total power generation 'Pg+x*R'  should be 
>>>>>> calculated from the generator cost information and not from the reserve 
>>>>>> costs ( I have tried that by making all the reserve costs zero). In 
>>>>>> addition to these I have no zonal reserve requirement ( I have made the 
>>>>>> constraint deactivated and deleted the second row of the 
>>>>>> mpc.reserves.zones, deactivated mpc.reserves.req and also deactivated 
>>>>>> where  'req' has been implemented). 
>>>>>> 
>>>>>> 
>>>>>> Can you suggest how can how I do it? or do you have any comments on the 
>>>>>> process I am already following?
>>>>>> 
>>>>>> Just to illustrate more on the reserve cost modification:
>>>>>> 
>>>>>> For example, I have 'Pg' from  a particular generator  (generator 1) 5 
>>>>>> MW, now after implementing the reserve , it is supplying another 1 MW 
>>>>>> from its capacity (it's Pmax is 10 MW). Now what I want is that this 
>>>>>> (5+1)=6 MW generation cost to be calculated by using the polynomial cost 
>>>>>> information from the mpc.gencost section. 
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>> On Tue, Apr 9, 2019 at 10:38 AM Ray Zimmerman <[email protected] 
>>>>>> <mailto:[email protected]>> wrote:
>>>>>> I think it might help me to have a high-level view of what you are 
>>>>>> trying to accomplish. If you are simply trying to *use* the already 
>>>>>> implemented fixed reserve capability, you shouldn’t need to even concern 
>>>>>> yourself at all with the implementation (i.e. the Ar matrix and the 
>>>>>> various callback functions, etc.). In that case, all you need is to 
>>>>>> understand the inputs in Table 7-5. If, on the other hand, you are 
>>>>>> modifying the implementation to do something other than what is 
>>>>>> currently implemented, then I need to understand what that is.
>>>>>> 
>>>>>> In what is already implemented, the generation cost is simply the cost 
>>>>>> of Pg. There is a separate cost of R that is added as a user cost. See 
>>>>>> (7.3). So the cost coefficients of R are provided in mpc.reserves.cost 
>>>>>> (see Table 7-5).
>>>>>> 
>>>>>>     Ray
>>>>>> 
>>>>>> 
>>>>>> 
>>>>>>> On Apr 8, 2019, at 2:39 PM, Jubeyer Rahman <[email protected] 
>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>> 
>>>>>>> Hi,
>>>>>>> 
>>>>>>> I have another few questions regarding the addition of the fixed zonal 
>>>>>>> reserves. So, far I understand, after adding the reserves, the real 
>>>>>>> power output of the generator will be added with reserve amount, so in 
>>>>>>> the part of the objective function where real power cost is being 
>>>>>>> calculated, which power is fed into as for calculation is it the 'Pg' 
>>>>>>> part of 'Pg+R' or is it the total 'Pg'? 
>>>>>>> 
>>>>>>> If I want to implement a reation like 'Pg+x*R' , where x is a 
>>>>>>> collection of parameters (n-by-1) , which place can I feed into these 
>>>>>>> parameters? I am assuming, this should be the second column of the Ar 
>>>>>>> matrix. Is that correct?
>>>>>>> 
>>>>>>> Regards
>>>>>>> 
>>>>>>> 
>>>>>>> 
>>>>>>> On Fri, Apr 5, 2019 at 10:53 AM Jubeyer Rahman <[email protected] 
>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>> Please ignore the last email, I have figured this out. Every column in 
>>>>>>> the first row corresponds the generators supposed to participate in the 
>>>>>>> reserve provision , that's why they are made one.
>>>>>>> 
>>>>>>> On Wed, Apr 3, 2019 at 5:27 PM Jubeyer Rahman <[email protected] 
>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>> Are you talking about the columns in the second row?
>>>>>>> 
>>>>>>> On Mon, Apr 1, 2019 at 5:21 PM Ray Zimmerman <[email protected] 
>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>> The only thing you need to do is make sure the corresponding column in 
>>>>>>> mpc.reserves.zones is all zeros.
>>>>>>> 
>>>>>>>    Ray
>>>>>>> 
>>>>>>>> On Apr 1, 2019, at 10:31 AM, Jubeyer Rahman <[email protected] 
>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>> 
>>>>>>>> Ok, I got your point and realized my mistake in understanding the zone 
>>>>>>>> handling section. So, if I want some of the generator's choosing not 
>>>>>>>> to provide ramp, should just setting the element of Identity matrix's 
>>>>>>>> corresponding rows of first column of Ar be Ok? or I may need to 
>>>>>>>> change something else as well?
>>>>>>>> 
>>>>>>>> On Mon, Apr 1, 2019 at 9:45 AM Ray Zimmerman <[email protected] 
>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>> Regarding your first question, as described by (7.2) in the User’s 
>>>>>>>> Manual, the reserve for a given generator is bounded above by both any 
>>>>>>>> limit provided in mpc.reserves.qty (r_i^{max}) and by any physical 
>>>>>>>> ramp rate (∆_i) given in mpc.gen(:, RAMP_10). It just so happens that 
>>>>>>>> the example in t_case30_userfcn does not specify any physical ramp 
>>>>>>>> rates, but the code still needs to handle cases which *do* provide 
>>>>>>>> physical ramp limits.
>>>>>>>> 
>>>>>>>> I’m not sure why you say only two generators are supposed to take part 
>>>>>>>> in the reserve provision. In t_case30_userfcn there are two reserve 
>>>>>>>> zones defined, but all 6 generators are able to participate in 
>>>>>>>> providing the required reserves.
>>>>>>>> 
>>>>>>>> You may want to review carefully the formulation in (7.2)–(7.5) and 
>>>>>>>> Table 7-2.
>>>>>>>> 
>>>>>>>>    Ray
>>>>>>>> 
>>>>>>>> 
>>>>>>>> 
>>>>>>>>> On Mar 29, 2019, at 4:06 PM, Jubeyer Rahman <[email protected] 
>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>> 
>>>>>>>>> Referring to the 'userfcn_reserves_formulation', there is a line 
>>>>>>>>> which is finding the value of k, which seems to be zero since none of 
>>>>>>>>> the data in  'Ramp_10' column  in t_case_30_userfcn is all zeros. so 
>>>>>>>>> I don't see any point of using the line 
>>>>>>>>> 
>>>>>>>>> Rmax(k)=mpc.gen(k,Ramp_10), can you explain why the code is written 
>>>>>>>>> that way.
>>>>>>>>> 
>>>>>>>>> From my understanding only two generators are supposed to take part 
>>>>>>>>> in the reserve provision, but the while putting the value for Rmax 
>>>>>>>>> and Rmin, the code is considering all of them, which looks kind of 
>>>>>>>>> unreasonable to me. Can you please explain this section as well?
>>>>>>>>> 
>>>>>>>>> Regards,
>>>>>>>>> Jubeyer
>>>>>>>>> 
>>>>>>>>> On Fri, Mar 29, 2019 at 12:43 PM Ray Zimmerman <[email protected] 
>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>> That is correct. All of the callbacks are technically optional. 
>>>>>>>>> Typically you need the formulation callback to implement the actual 
>>>>>>>>> problem modifications, and possibly ext2int and int2ext if you need 
>>>>>>>>> to do some handling of input and output data, respectively. The 
>>>>>>>>> printpf and savecase callbacks are only needed if you want to add 
>>>>>>>>> things to the standard pretty-printed output or saved case data.
>>>>>>>>> 
>>>>>>>>>     Ray
>>>>>>>>> 
>>>>>>>>> 
>>>>>>>>>> On Mar 29, 2019, at 12:15 PM, Jubeyer Rahman <[email protected] 
>>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>>> 
>>>>>>>>>> Just how important it is to include printpf and savecase callback 
>>>>>>>>>> during the extension of OPF, if I don't really need anything printed 
>>>>>>>>>> out right after I call the power flow? Will it be still possible to 
>>>>>>>>>> extract information from the 'results' when I say 
>>>>>>>>>> results=runopf(mycase)?
>>>>>>>>>> 
>>>>>>>>>> To my understanding, after runopf being called, 'results' struct 
>>>>>>>>>> will be returned and can be accessed by writing some command like 
>>>>>>>>>> results.gen(:,2), etc. Let me know if I am thinking correctly or not?
>>>>>>>>>> 
>>>>>>>>>> On Fri, Mar 29, 2019 at 9:53 AM Jubeyer Rahman <[email protected] 
>>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>>> Thank you very much.
>>>>>>>>>> 
>>>>>>>>>> On Fri, Mar 29, 2019 at 8:43 AM Ray Zimmerman <[email protected] 
>>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>>> Are you attempting to use the provided extension for fixed reserves, 
>>>>>>>>>> or are you attempting to write your own extension?
>>>>>>>>>> 
>>>>>>>>>> If it’s the former, the full implementation is included in 
>>>>>>>>>> toggle_reserves() 
>>>>>>>>>> <http://www.pserc.cornell.edu/matpower/docs/ref/matpower6.0/toggle_reserves.html>.
>>>>>>>>>>  Simply load your case file, use toggle_reserves() to enable the 
>>>>>>>>>> callbacks, then run the OPF (or just call runopf_w_res() 
>>>>>>>>>> <http://www.pserc.cornell.edu/matpower/docs/ref/matpower6.0/runopf_w_res.html>,
>>>>>>>>>>  which does these 3 steps automatically for you).
>>>>>>>>>> 
>>>>>>>>>> If you are attempting to write your own extension, I suggest making 
>>>>>>>>>> a copy of toggle_reserves.m and rename it and all of the functions 
>>>>>>>>>> in it and use it as a template for your own extension.
>>>>>>>>>> 
>>>>>>>>>>    Ray
>>>>>>>>>> 
>>>>>>>>>> 
>>>>>>>>>>> On Mar 28, 2019, at 12:40 PM, Jubeyer Rahman <[email protected] 
>>>>>>>>>>> <mailto:[email protected]>> wrote:
>>>>>>>>>>> 
>>>>>>>>>>> Hi,
>>>>>>>>>>> 
>>>>>>>>>>> Recently I was digging through the extending OPF chapter of 
>>>>>>>>>>> Matpower manual, but I don't quite catch the process. Regarding the 
>>>>>>>>>>> example given there on 'Fixed zonal reserves' what I understand 
>>>>>>>>>>> from my reading is, it is required to write down a call back 
>>>>>>>>>>> function for formulation along with some call of callback 
>>>>>>>>>>> functions. I have followed every steps mentioned there but could 
>>>>>>>>>>> not make the code run (I am using version 6.0). I am adding my code 
>>>>>>>>>>> snippet here for better conveying.
>>>>>>>>>>> 
>>>>>>>>>>> %%%
>>>>>>>>>>> mpc=loadcase('case30.m');
>>>>>>>>>>> mpopt = mpoption('out.all', 0, 'verbose', 0);
>>>>>>>>>>> mpc=add_usefcn(mpc,'formulation',@userfcn_reserves_formulation);
>>>>>>>>>>> mpc=ext2int(mpc,mpopt);
>>>>>>>>>>> results=runopf(mpc);
>>>>>>>>>>> results=int2ext;
>>>>>>>>>>> 
>>>>>>>>>>> %%%%
>>>>>>>>>>> Error message:
>>>>>>>>>>> Access to an object's fields is only permitted within its methods.
>>>>>>>>>>> 
>>>>>>>>>>> I have added the mpc.reserve data(cost, req, zones) posted in 
>>>>>>>>>>> 't_case30_userfcns.m' file.
>>>>>>>>>>> I have written the userfcn_reserves_formulation in a different 
>>>>>>>>>>> script , but  it is not working.
>>>>>>>>>>> I didn't write the add_var and add_constraint explicitly since the 
>>>>>>>>>>> add_userfcn callback function already contains those.
>>>>>>>>>>> 
>>>>>>>>>>> Can you tell me what I am missing?
>>>>>>>>>>> 
>>>>>>>>>>> Regards,
>>>>>>>>>>> Jubeyer
>>>>>>>>>>> 
>>>>>>>>>> 
>>>>>>>>> 
>>>>>>>> 
>>>>>>> 
>>>>>> 
>>>>> 
>>>> 
>>> 
>> 
> 

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