Francisco Jose Montilla wrote: (in reply to Jim Coon)
> That doesn't happen in the amp/transducer world, AFAIK. Here
> weren't working with DC, is variable Hz AC, and what
Sorry Francisco, I'm having a lot of difficulty in understanding what you
are trying to say. Jim's equation works with AC or DC.
> actually happens if my memory serves me well is that current voltage
> increases, and power decreases. (hence my doubt).
What is "current voltage" ? Power = current * voltage.
> That's why amps tend to produce better sound
> when using higher impedances.
I'd like to see some evidence for this. I suspect the impedance only really
affects the volume (More impedance = less power)
simon
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