Francisco Jose Montilla wrote:

 
    > I meant (sorry, english isn't my native language) that 
    > what excite the headphone transducers is a variable (AC) electrical 
    > signal. I don't have the mathematical demonstration handy, but if you
go 
    > in a little deeper, you'll notice that with higher loads (i.e. 
    > impedances) peak voltage rises. Those equations assume a constant
(i.e. 
    > DC) voltage. 

The voltage across the load will increase in proportion to the impedance if
it is fed by a current source. Most amplifiers act as (effectively) VOLTAGE
sources, in which case the current in the load falls as the impedance rises.

 
    > My doubt is, if a 200 Ohm headphones with higher 
    > sensitivity than a 32 Ohm headphones <snip> which will drain more
battery.
    > I'd bet the 200 Ohm, but am not sure...
    > I'd try to reproduce the equation development to prove the
    > voltage raise.

Good luck ! I'll be glad to see Herr Ohms' outdated law exposed for the
fraud that it is :-)

simon
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