On Mon, Mar 09, 2009 at 02:43:27PM -0700, Peter Memishian wrote: > > > > I've gone through the materials, and I have one question about the new > > > behavior for ::print: how does it disambiguate the command line? > > > > > > For example, if I do this: > > > > > > > ::walk foo | ::print bar > > > > > > is "bar" a member of whatever sort of structure the "foo" list > > > contains, or is "bar" the type of object I want to print in its > > > entirety? > > > > It builds upon the (possibly broken) current behavior: > > > > 1. if "bar" resolves as a type, we use that, or > > 2.* if there's a valid pipe type, we use that, or > > 3. if addr is a symbol with associated type info, we use that. > > > > (* is the new behavior). This, unfortunately, has the DWIM nature, and > > there's no current way to disambiguate it. > > I would've expected one can override and get (3) by doing "::print `bar"
How would that help? The syntax is: bar::print ... Cheers, - jonathan
