Katharina Wolkwitz wrote: > Hi again! > > I think I've found the solution to my problem: > > Changing the following line in accesscontrol.php from: > > function doControlUserAccess( $input, $argv, &$parser )
prototype means the third parameter is a reference. Since it was given a value, per the error message, changing the prototype to > function doControlUserAccess( $input, $argv, $parser ) fixes it. _______________________________________________ MediaWiki-l mailing list [email protected] https://lists.wikimedia.org/mailman/listinfo/mediawiki-l
