Sigbert Klinke asks about <sample>:
>is called is there a way to get the tag name "sample" itself inside [a tag
>extension]?
I am pretty sure the answer is no. I worked around it by defining my callbacks
dynamically, one per tag.
Suppose you are writing 3 tags named <A>, <B>, and <C>.
You can dynamically create a callback function for each one, passing the tag
name to it, something like this:
public static function initTags(Parser &$parser) {
foreach (array('A', 'B', 'C') as $tagName) {
$callback = function($argv) use ($tagName, $parser) {
return Tags::processTag($tagName, $argv, $parser);
};
$parser->setHook($tagName, $callback);
}
return true;
}
Now the function processTag() knows the tag name, and you can write it to do
whatever you want.
DanB
_______________________________________________
MediaWiki-l mailing list
To unsubscribe, go to:
https://lists.wikimedia.org/mailman/listinfo/mediawiki-l
