Thanks, Brian! I tried it out, and that worked great. Somehow I never thought to check how other extensions do it...
On Mon, Feb 15, 2021 at 9:09 PM Brian Wolff <bawo...@gmail.com> wrote: > You need to call $frame->expand( $argument ) on each argument value to get > the actual value. #if is an example of doing this > https://github.com/wikimedia/mediawiki-extensions-ParserFunctions/blob/master/includes/ParserFunctions.php#L118 > . > > This structure is to allow dead code elimination. Any argument not > expanded is not processed which has an effect on efficiency. Most of the > time that's not something to worry about, but it makes a big difference for > control structures like #if. > > > I probably should have said Parser::SFH_OBJECT_ARGS instead of just > SFH_OBJECT_ARGS. I think the non class prefixed constant is deprecated. > > -- > Brian > > On Monday, February 15, 2021, Yaron Koren <ya...@wikiworks.com> wrote: > >> Hi Brian, >> >> Thank you! That... mostly worked. I added SFH_OBJECT_ARGS >> to setFunctionHook(),and then the new $frame value passed in was indeed >> easy to use - I just had to call $frame->getArgument('ParameterName')" to >> get the value for that template parameter. >> >> Unfortunately, now I don't know how to get all of the actual arguments to >> the parser function. Before, the call func_get_args() did that. Now, >> neither that function, nor just getting the $args argument, seems to get >> all the arguments - I think they get arguments that are entirely static, >> but an argument like "flag image={{{Flag image|}}}" leads to a strange >> structure within $args that doesn't seem to include the actual value. Is >> there a fix for that? >> >> -Yaron >> >> On Mon, Feb 15, 2021 at 1:02 PM Brian Wolff <bawo...@gmail.com> wrote: >> >>> I think what you have to do is set the SFH_OBJECT_ARGS flag in the >>> third argument of setFunctionHook. >>> >>> That will change the function signature of your callback to ($parser, >>> $frame, $args). Note that $args might no longer be an array of strings but >>> PPNode (or something) stuff you may have to call $frame->expand() on (i >>> think. It was something like that). >>> >>> This new form has a PPFrame object as a second arg. You should be able >>> to call $frame->getParent() on it which should give you what you need. >>> >>> -- >>> Brian >>> >>> On Monday, February 15, 2021, Yaron Koren <yaro...@gmail.com> wrote: >>> >>>> Hi, >>>> >>>> When you have a parser function called from within a template, you can >>>> of course pass in to it any template parameters, like: >>>> >>>> {{#flagicon:{{{Flag image|}}} }} >>>> >>>> (This is a silly example, but bear with me.) I would like to instead be >>>> able to call the parser function without the parameter, like this: >>>> >>>> {{#flagicon:}} >>>> >>>> ...and have the parser function directly get the value of the "Flag >>>> image" parameter. >>>> >>>> I believe this can be done within Lua: when a Lua module is invoked >>>> from a template, it can get the names and values of the >>>> parameters/arguments that have been passed to that template using (I >>>> believe) code that looks like the following: >>>> >>>> frame = mw.getCurrentFrame() >>>> origArgs = frame:getParent().args >>>> >>>> I tried to do something similar within a parser function's code, using >>>> various calls like the following, but nothing worked: >>>> >>>> $frame = $parser->getPreProcessor()->newFrame()->newChild(); >>>> $args = $frame->getArguments(); >>>> >>>> Can this be done? Ideally, it would be great to get an array of all the >>>> arguments that have been passed to the template - but just being able to >>>> get the value for a specified parameter name would be good enough. >>>> >>>> -Yaron >>>> >>>> -- >>>> WikiWorks · MediaWiki Consulting · http://wikiworks.com >>>> >>> _______________________________________________ >>> MediaWiki-l mailing list >>> To unsubscribe, go to: >>> https://lists.wikimedia.org/mailman/listinfo/mediawiki-l >>> >> >> >> -- >> WikiWorks · MediaWiki Consulting · http://wikiworks.com >> > _______________________________________________ > MediaWiki-l mailing list > To unsubscribe, go to: > https://lists.wikimedia.org/mailman/listinfo/mediawiki-l > -- WikiWorks · MediaWiki Consulting · http://wikiworks.com
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