Hi, fcen is the central frequency as described in your ctl.file, fcen = a/lambda=1/1.55=0.645 df is the pulse width or delta_w and should be equal to: 0.1 or 0.2 or 0.3 or 0.4 and so on if u choose for example df=0.2, u have w_min= fcen-df/2=0.645-0.2/2=0.645-0.1=0.545 and w_max=fcen+df/2=0.645+0.1=0.745, so you cover a sperctra from 0.545 to 0.745. nfreqs is the number of point that cover all range of frequencies, w_min and w_max and should be equal to 301, 501, as u like hope this help you with regards --- On Tue, 4/27/10, Sanchit Khatavkar <[email protected]> wrote:
From: Sanchit Khatavkar <[email protected]> Subject: Re: [Meep-discuss] How to get the transmitted power for a fixed frequency (Continuous wave source) To: [email protected], "Alexandr Sadovnikov" <[email protected]> Date: Tuesday, April 27, 2010, 2:45 AM Dear Alexandr, Thanks for your reply. You are right. The CW source has only one frequency in the flux spectrum. I am attaching my ctl file for your reference. "add-flux" needs 3 parameters, namely "fcen" "df" "nfreq" alongwith the flux-regions... (Quoting from Meep Reference) Since a continuous source sends out light of a single frequency, what do we specify for "df" and "nfreq". As a trial, I gave the fixed frequency as "fcen", 0 as "df" and 1 as "nfreq". I am not sure whether if this is the right approach. Kindly advise. Regards, Sanchit -----Inline Attachment Follows----- _______________________________________________ meep-discuss mailing list [email protected] http://ab-initio.mit.edu/cgi-bin/mailman/listinfo/meep-discuss
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