I see. Just to clarify what I understand from Trond's proposal: - If given mem limit satisfies each slab class then preallocate everything(all slabs, chunks...etc..). - If given mem limit does not satisfy all slab classes then fallback to system malloc.
Is this correct? Thanks, On Aug 25, 1:17 am, dormando <[email protected]> wrote: > > I am currently fiddling with the slab allocator and one thing messes > > my understanding of the concept. Think about the following scenario: > > > 1) start memcached with ./memcached -m 1 (with 1 Mb of memory limit) > > 2) set mykey 0 0 11 --> allocates a 1 Mb slab and a chunk is returned > > for about the smallest possible chunk > > 3) set mykey2 0 0 200 -- ? > > > Now I cannot understand what happens in the 3rd step? There is no > > memory left for another slab error returned or something else? I have > > tried to test this on my machine but somehow cannot interpret the > > results correctly. 2nd step does allocate 1 MB of slab with 96 bytes > > of chunk size? I am right? > > http://code.google.com/p/memcached/issues/detail?id=95 > > will be fixed at some point...
