Hello,
because of the discussion about the speed on the slowest exponents I did
some calculations:
Result:
The limits like 750 MHz or even 350 MHz for the smalles exponents are
completely ridiculous, certainly if we do not take into account the number
of it is on, a 1000 MHz machine on for 8x5 hours a week will take longer
than PII 233 on 24x7.
If we want to get it done as soon as possible we must calculate what would
be fastest:
Observation the relatively slow machines are often used as servers / private
firewalls and on 24x7
On the other hand relatively slow machines may be hardly on.
Some calculations (benchmark page) on the fictive exponent 4000000 yields
24x7 on a:
486@33: 1Y+182 days (Ok that seems long)
PI@60: 43 days (Seems we can wait on that, as long as the machine is
reliable)
PII@233: 10 days (Seems as of now it really does not matter anymore)
Cel@300: 8 days
PIII@450: 6 days
PIII@1000: 3 days
Athlon@1200: 2 days
Some calculations on the ficive exponent 8000000 (486 left out)
PI@60 : 177 days (Doubtfull)
PII@233 : 40 days (Seems we can wait on that, as long as the machine is
reliable)
Cel@300 : 31 days
PIII@450 : 23 days
PIII@1000 : 12 days
Athlon@1200 : 9 days
Some calculations on the ficive exponent 12000000 (486 left out)
PI@60 : 1Y+29 days (Seems to long)
PII@233 : 87 days
Cel@300 : 68 days
PIII@450 : 50 days
PIII@1000 : 27 days
Athlon@1200 : 17 days
When we take into account that the timeout offset is 60 days (so someone
starting an assignment and not doing anything at all costs 60 days, nobody
works on the exp. so that is a delay of the entire project) We should
probably reassign exponents to machines that have already
finished at least 2 exponents, and based on that info will return this
assignment within 60 days.
That would be like doublechecks reassigns for PI / PII / Celeron, Primality
reassigns for PIII / Athlon.
Exponents in the lower 10% of a range should be reassigned if no progress
has been reported for 60 days.
A good better solution optimizing for progress would be to re-assign expired
exponents to machines that have finished exponents already and will finish
them in for instance approximately 20 days (Assigning the smaller exponents
to slower machines and larger exponents to faster machines) The actual
number of days can be calculated from the "ballpark". So that optimal
progress is made. We must try to keep slow machines in as long as possible
as they really contribute to the progress.
So optimal progress will be made by giving smaller machines small exponents
and larger machines large.
Kind Regards, Martijn
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