If one side is NaN, then
!(x == y) is true, whereas x != y is false
On 25/05/2015 21:01, Ilia Mirkin wrote :
On Mon, May 25, 2015 at 2:53 PM, Matt Turner <[email protected]> wrote:
It's that the compiler thinks that (!x == y) is a typo for !(x == y).
I have to say, I think the first does look strange.
I dunno... the second looks way stranger. x != y seems way more
natural. While there's no substantially better way to write !x == y.
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